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IgorC [24]
3 years ago
12

An ideal vapor-compression refrigeration cycle using refrigerant-134a as the working fluid is used to cool a brine solution to −

5°C. This solution is pumped to various buildings for the purpose of air-conditioning. The refrigerant evaporates at −10°C with a total mass flow rate of 7 kg/s, and condenses at 600 kPa. Determine the COP of the cycle and the total cooling lo
Engineering
1 answer:
Semenov [28]3 years ago
8 0

Answer:

1141

7.2

Explanation:

The evaporator Temperature T1 = -10°C

h1 = 244.55kj/kg

S1 = 0.93782kj/kg

The enthalpy at second state from given condenser pressure from super heated refrigerant table

P2 = 600

S2 = S1

h2 = 267.19kj/kg

Enthalpy at 3 and 4 from condenser pressure

h3 = h4 = 81.5kj/kg

To get cooling load

QL = m(h1-h4)

M= 7

= 7(244.55-81.5)

= 7(163.05)

= 1141.35kw = 1141KW

COP

= h1-h4/h2 -h1

= 244.55-81.5/267.19-244.55

= 163.05/22.64

= 7.2

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Montano1993 [528]

Answer:

τ = 0.25 lbf/in²

Explanation:

given that the oil viscosity, μ =  2.415 lb/ft-s

gap between plates = 1/4 inches = 1/4*12 = 1/48 ft

recall from newtons law of viscosity;

shear stress τ = μ du/dy =

  τ = (2.415 lb/ft-s) (10 ft/s)/(1/48) ft

τ = 1159.2 lb/ft-s²

we know that, 1 slug = 32.174 lb

lb = 1/32.174 slug

∴  τ = 1159.2/32.174 slug/ft-s² = 36 slug/ft-s²

τ = 36 slug/ft-s²

multiply both the numerator and denominator by ft, this gives

τ = 36 slug-ft/ft²-s²

τ = 36 lbf/ft² where 1 slug-ft/s² = 1lbf

since 1 ft = 12 inch = 1 ft² = 12² in² = 144 in²

∴  τ = 36/144 lbf /in² = 0.25 lbf/in²

τ = 0.25 lbf/in²

6 0
3 years ago
Diana and Kinsey are put in charge of choosing a mascot for their basketball team. There are fifteen players on the team, but Di
arsen [322]

Answer:

the data are inadequate

Explanation:

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Sasha goes back through her architectural design books for inspiration and designs the new country club to have a Romanesque fee
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3 years ago
At what distance should the warning triangle be placed if a vehicle breaks down on the autobahn?
igor_vitrenko [27]

Answer:

The answer is 200 Meters

Explanation:

At what distance should the warning triangle be placed if a vehicle breaks down on the autobahn?

200 Meters

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4 0
4 years ago
Air is pumped from a vacuum chamber until the pressure drops to 3 torr. If the air temperature at the end of the pumping process
malfutka [58]

Answer:

The final pressure is 3.16 torr

Solution:

As per the question:

The reduced pressure after drop in it, P' = 3 torr = 3\times 0.133\ kPa

At the end of pumping, temperature of air, T = 5^{\circ}C = 278 K

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Now, we know the ideal gas eqn:

PV = mRT

So

P = \frac{m}{V}RT

P = \rho_{a}RT          (1)

where

P = Pressure

V = Volume

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R = Rydberg's constant

T = Temperature

Using eqn (1):

P = \rho_{a}RT

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Now, at constant volume the final pressure, P' is given by:

\frac{P}{T} = \frac{P'}{T'}

P' = \frac{P}{T}\times T'

P' = \frac{3}{278}\times 293 = 3.16 torr

7 0
4 years ago
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