We are asked to convert 25 cg to units of hg.
1 cg = 1 centigram = 10⁻² g
1 hg = 1 hectogram = 10² g
The options given are:
a) 1 hg/ 10² g
b) 10² cg/ 1 hg
c) 10² hg/ 1 cg
d) 10⁻² g/ 1 cg
To convert 25 cg to 1 hg, we could convert the 25 cg to grams first, then grams to hg.
25 cg · 10⁻² g/ 1cg = 0.25 g
Here we have converted our number from cg to grams. We can use another conversion of grams to hg to complete the conversion.
0.25 g · 1 hg/ 10² g = 0.0025 hg
Therefore, the first conversion we used was d) 10⁻² g/ 1 cg.
Answer:
For gases such as hydrogen, oxygen, nitrogen, helium, or neon, deviations from the ideal gas law are less than 0.1 percent at room temperature and atmospheric pressure. Other gases, such as carbon dioxide or ammonia, have stronger intermolecular forces and consequently greater deviation from ideality.
Explanation:
Answer: Phosphorus is insoluble in water, but soluble in carbon disulfide. Phosphorus burns spontaneously in air to its pentoxide.
Explanation: Hope this helped! :)
A common use of bases is to reduce indigestion. Hence, option D is correct.
<h3>What is the base?</h3>
A base is a substance that can neutralize the acid by reacting with hydrogen ions.
Bases are substances whose solutions have a pH value of more than 7. Bases are bitter in taste.
Whereas acids are the substances whose solutions have a pH value of less than 7. Acids are sour in taste.
When an excess of acid is formed in the human stomach then an antacid tablet which is basically a base is consumed that helps in reducing indigestion.
Therefore, we can conclude that the common use of bases is to reduce indigestion.
Learn more about the base here:
brainly.com/question/1432645
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The higher levels of gravity put on an object the more weight the object has. For example someone who weighs say 100 lbs would weigh more if higher amounts of gravity would be applied to them. And less if less gravity was applied. But larger objects will automatically have more gravity applied to them than something smaller due to the gravitational pull needing to pull harder to keep the object to the planet's surface. Hope this helps! :)