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2 years ago

Implement pollution reduction strategies that are needed to clean up the river ????

Chemistry

1 answer:

miss Akunina [59]2 years ago

8 0

Answer:

* Properly dispose of hazardous household items.

* Reduce or eliminate use of fertilizers and chemical herbicides and pesticides.

* Make an appointment to service your septic system

Landscape with native plants.

* Eliminate bare spots in your yard.

* Make a rain garden.

WAS THIS HELPFUL......

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What is different about the rotation of Uranus?

Trava [24]

Answer:

Unlike the other planets of the solar system, Uranus is tilted so far that it essentially orbits the sun on its side, with the axis of its spin nearly pointing at the star. This unusual orientation might be due to a collision with a planet-size body, or several small bodies, soon after it was formed.

Explanation:

the axis is vertical

7 0

3 years ago

Whitney's lung capacity was measured as 3.3 l at a body temperature of 37 ∘c and a pressure of 746 mmhg . how many moles of oxyg

myrzilka [38]

the ideal gas equation is PV=nRT
where P=pressure
V=Volume
n=no. of moles
R=universal gas constant
T=temperature
The universal gas constant (R) is 0.0821 L*atm/mol*K
a pressure of 746 mmhg =0.98 atm= 1 atm (approx)
T=37 degrees Celsius =37+273=310 K (convert it to Kelvin by adding 273)
V=0.7 L (only getting oxygen, get 21% of 3.3L)
Solution:
(1 atm)(0.7 L)=n(0.0821 L*atm/mol*K)(310 K)
0.7 L*atm=n(25.451 L*atm/mol)
n=0.0275 mole
Answer:
n=0.0275 mole of oxygen in the lungs.

4 0

3 years ago

Determine % yield if a student obtains 45 g of product in an experiment and the theoretical amount is determined to be 50 g

Katen [24]

Percentage yield=(actual yield/theoretical yield) x 100%
= (45/50) x 100%
= 90%

8 0

4 years ago

Suppose the concentration of the standard stock solution is 50.04 ppm and that you delivered 4.60 mL of this standard stock solu

12345 [234]

Answer:

9.21 ppm

Explanation:

Considering

$concentration_{working\ solution}\times Volume_{working\ solution}=concentration_{stock\ solution}\times Volume_{stock\ solution}$

Given that:

$concentration_{working\ solution}=?$

$Volume_{working\ solution}=25.00mL$

$Volume_{stock\ solution}=4.60mL$

$concentration_{stock\ solution}=50.04 ppm$

So,

$concentration_{working\ solution}\times 25.00mL=50.04 ppm\times 4.60mL$

$concentration_{working\ solution}=\frac{50.04\times 4.60}{25.00}\ ppm=9.21\ ppm$

4 0

3 years ago

Intermolecular forces are the interactions between molecules and are generally weaker than bonds within molecules. Which molecul

telo118 [61]

Answer:

Molecules that will have dipole-dipole forces with like molecules include the water (H2O) molecule. Another example is the Hydrogen Chloride (HCl) molecule.

Explanation:

Intermolecular forces are forces of attraction or repulsion that exist between particles (ions, atoms, or molecules) that are close/in nearby proximity to each other. Usually, intermolecular forces are not as strong as intramolecular forces which create covalent or ionic bonds between the atoms that exist within molecules. Dipole-dipole interactions occur whenever the partial charges that exist within one molecule are attracted to the opposite partial charges that exist within another different molecule that is nearby and similar in composition: the positive end/charges of one molecule are attracted to the negative end/charges of another similar molecule.

An example of molecules that exhibit dipole-dipole interaction is the water (H2O) molecule. Another molecule which exhibits dipole–dipole interaction is the Hydrogen Chloride (HCl) molecule, whereby the positive end of one HCl molecule usually attracts the negative end of another HCl molecule.

6 0

3 years ago