2.0 L
Answer:
Solution given:
no. of mole(n)=3.0mole
molarity(M)=1.5M
we have
<u>Volume of a substance is equal to the ratio of its no of mole to its molarity.</u>
By this we get a relation:
Volume=no.of mole/molarity
substituting value
Volume=3.0/1.5=2
The required volume is 2 litre.
Answer:
NaOH is the limiting reactant.
Explanation:
Hello there!
In this case, since the reaction taking place between sodium hydroxide and chlorine has is:
Which must be balanced according to the law of conservation of mass:
Whereas there is a 2:1 mole ratio of NaOH to Cl2, which means that the moles of the former that are consumed by 0.85 moles of the latter are:
Therefore, since we just have 1.23 moles out of 1.70 moles of NaOH, we infer this is the limiting reactant.
Regards!
Answer:
Explanation:
The following compounds are soluble in water and will dissociate when dissolved in water.
A) barium hydroxide
B) ethanol
C) glucose
D) silver nitrate
E) dichloromethane
F) postassium chloride
The other compounds ethanol and glucose are also soluble in water but do not dissociate when dissolved in water.
If you graph the heat added to a system versus the system's temperature, the graph usually slopes upward; adding heat increases temperature.