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Alex787 [66]
3 years ago
13

Some distilled water is added to an empty beaker. a gram of copper (ii) nitrate is added to the beaker and while the water is be

ing stirred. after a few minutes, what is in the beaker?
Chemistry
1 answer:
Xelga [282]3 years ago
6 0
Copper ions, nitrate ions, and water is in the beaker
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14 Copper(II) oxide reacts with hydrogen.
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Answer:

B

CuO

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Explanation:

hydrogen will oxidized to form water

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Ration for molar volume. 1 mole=___L at STP
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In a periodic table, dots around an elements symbol indicate the number of valence electrons in an atom ? True Or False
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The temperature in a beaker of water is 50 degrees Celsius. Kiley puts the water into a freezer. After a few minutes, she measur
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Answer:

This question lacks options; the options are:

A) They moved more freely

B) They moved closer together.

C) The average speed increased.

D) The average kinetic energy increased

The answer is B

Explanation:

The water in the beaker is described to be in a liquid state of matter. Its temperature decreases from 50°C to 10°C when placed in a freezer by Kiley. This means that heat is gradually being lost as the liquid water undergoes freezing into a solid state.

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5 0
3 years ago
Suppose 0.708g of copper(II) acetate is dissolved in 50.mL of a 46.0mM aqueous solution of sodium chromate.
lisabon 2012 [21]

Answer:

The final molarity of acetate anion in the solution is 0.0046 moles

Explanation:

The balanced equation is

Cu(C₂H₃O₂)₂ + Na₂CrO₄ = CuCrO₄ + 2Na(C₂H₃O₂)

Therefore one mole of Cu(C₂H₃O₂)₂ react with one mole of Na₂CrO₄ to form one mole of CuCrO₄ and two moles of Na(C₂H₃O₂)

Mass of copper (II) acetate present = 0.708 g

Volume of aqueous sodium present = 50 mL

Molarity of sodium chromate = 46.0 mM

Therefore

Number of moles of sodium chromate present = (50 mL/1000)×46/1000 = 0.0023 M

Number of moles of copper (II) acetate present = 181.63 g/mol

number of moles of copper (II) acetate present = (0.708 g/181.63 g/mol) =0.0039 moles

Therefore 0.0039 moles of Cu(C₂H₃O₂)₂ × (2 moles of Na(C₂H₃O₂))/1 Cu(C₂H₃O₂)₂) = 0.00779 moles of Na(C₂H₃O₂)

also 0.0023 moles of Na₂CrO₄ × (2 moles of Na(C₂H₃O₂))/1 Na₂CrO₄) = 0.0046 moles of Na(C₂H₃O₂)

Therefore the Na₂CrO₄ is the limiting reactant and 0.0046 moles of Na(C₂H₃O₂) or acetate anion is formed

7 0
3 years ago
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