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Ronch [10]
3 years ago
7

When will Le Chatelier's principle come into effect?

Chemistry
1 answer:
True [87]3 years ago
6 0
If u disturbed equilibrium position then this principal comes into effect deciding how to counteract the disturbance.
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When a 500. gram sample of water at 19.0°C absorbs 8400 Joules of heat, the temperature of the water
Westkost [7]

Answer: 23.0ºC

Explanation:

Just trust me

7 0
3 years ago
Neutralization Reactions
marta [7]

Answer:

2HNO3+ Ba(OH)2 = Ba(NO3)2 + 2H2O

H3PO4 + Ca(OH)2 = Ca3(PO4)2 + 6H2O

Explanation:

2HNO3+ Ba(OH)2 = Ba(NO3)2 + 2H2O

H3PO4 + Ca(OH)2 = Ca3(PO4)2 + 6H2O

H+

O2-

OH-

Ba2+

Ca2+

NO3-

P 5+, 3+, 3-

H2O

4 0
3 years ago
22 Determine the molar mass of an unknown gas that has a volume of 72.5 mL at a temperature of 68C, and a pressure of 0.980 atm
jekas [21]

Answer:

81.5g/mol

Explanation:

Molar mass is the ratio between mass of a substance (In this case, 0.207g) and moles presents in this mass.

To solve this question we must find the moles of the gas in order to obtain the molar mass using:

PV = nRT

PV / RT = n

<em>Where P is pressure = 0.980atm</em>

<em>V is volume in Liters = 0.0725L</em>

<em>R is gas constant = 0.082atmL/molK</em>

<em>T is absolute temperature = 68°C + 273.15 = 341.15K</em>

<em />

0.980atm*0.0725L / 0.082atmL/molK*341.15K = n

2.54x10⁻³ moles = n

Thus, the molar mass of the gas is:

0.207g / 2.54x10⁻³ moles

<h3>81.5g/mol</h3>
5 0
3 years ago
Referencing the reasoning you used from #1, explain the difference between objects that feel hot and those that
dezoksy [38]

Answer:

The temperature of the cold water is lower than the warm one. So, when we put the hand in the warm from the cold water, our hand will absorb heat, causing the hand to feel hot. Thus, we can conclude that the more heat it absorbs, the more hotter it is. Whereas the more heat it releases, the colder it is.

6 0
3 years ago
The question is a picture pls help
Hoochie [10]

The unknown alcohol = 2-propanol

<h3>Further explanation</h3>

Given

volume = 50 ml

mass = 39.4 g

Required

The unknown alcohol

Solution

Density of sample :

= mass : volume

= 39.4 g : 50 ml

= 0.788 g/ml

The unknown alcohol at room temperature = liquid, so the unknown alcohol is 2-propanol because it has temperature range between -90 to 82 for liquid and the density = 0.788 g/ml

6 0
3 years ago
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