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1 year ago

What wave on the electromagnetic spectrum has the highest frequency?

Physics

2 answers:

Jet001 [13]1 year ago

6 0

Answer:

Explanation:

Answer: Gamma rays

Gamma rays have the highest frequency.

What is an electromagnetic wave?

An electromagnetic wave requires no medium for its propagation.

It consists of a spectrum of different wavelengths.

Different wavelengths of rays have different energies and different frequencies.

Higher frequency rays have the highest energies.

What is gamma-ray?

These are ionized radiations.

Gamma radiations are obtained from the decay of the atomic nucleus.

It has the highest frequency which is why it can penetrate through matter.

It has the smallest wavelength and highest energy.

The frequency of gamma rays is more than 10^19 cycles per second and wavelength less than 100 picometers.

Nadusha1986 [10]1 year ago

6 0

Answer:

<u>Gamma Rays</u>

Explanation:

Each part of the electromagnetic (EM) spectrum comprises photons with distinct energy levels, wavelengths, and frequencies. Gamma rays are the most energetic, have the shortest wavelengths, and have the highest frequencies.

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Answer:

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2 years ago

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2 years ago

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A current of 200mA through a conductor converts 40 joules of electrical energy into heat in 30 seconds determine the potential d

gladu [14]

Answer:

V = 6.65 [volt]

Explanation:

We must first find the power generated, power is defined as the amount of energy consumed or generated in a given time.

$P=\frac{E}{t}$

where:

P = power [w]

E = energy = 40 [J]

t = time = 30 [s]

$P =40/30\\P = 1.33[w]$

Now we can calculate the voltage or potential drop by means of the power, the power is calculated by means of the product of the voltage by the current.

$P =V*I$

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2 years ago

A large, 60 turn circular coil of radius 10.0 cm carries a current of 4.2 A. At the center of the large coil is a small 20 turn

Eddi Din [679]

To solve this problem we apply the concepts related to the electric torque generated by the electromagnetic field. Mathematically this Torque can be written under the following relation

$\tau = NIAB sin\theta$

Here,

N = Number of Turns

I = Current

A = Area

B = Magnetic Field

The maximum torque will be reached when the angle is 90 degrees, then we will have the following relation,

$\theta = 90\°C$

Magnetic Field is given at function of the number of loops, permeability constant at free space at the perimeter, then

$B = \frac{N\mu_0 I}{2\pi r}$

$B = \frac{(60)(4\pi * 10^{-7})(4.2)}{2\pi (0.1)}$

$B = 5.04*10^{-4}T$

Replacing at the first equation we have,

$T = (20)(\pi (0.005)^2)(1)(5.04*10^{-4})$

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