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2 years ago

What wave on the electromagnetic spectrum has the highest frequency?

Physics

2 answers:

Jet001 [13]2 years ago

6 0

Answer:

Explanation:

Answer: Gamma rays

Gamma rays have the highest frequency.

What is an electromagnetic wave?

An electromagnetic wave requires no medium for its propagation.

It consists of a spectrum of different wavelengths.

Different wavelengths of rays have different energies and different frequencies.

Higher frequency rays have the highest energies.

What is gamma-ray?

These are ionized radiations.

Gamma radiations are obtained from the decay of the atomic nucleus.

It has the highest frequency which is why it can penetrate through matter.

It has the smallest wavelength and highest energy.

The frequency of gamma rays is more than 10^19 cycles per second and wavelength less than 100 picometers.

Nadusha1986 [10]2 years ago

6 0

Answer:

<u>Gamma Rays</u>

Explanation:

Each part of the electromagnetic (EM) spectrum comprises photons with distinct energy levels, wavelengths, and frequencies. Gamma rays are the most energetic, have the shortest wavelengths, and have the highest frequencies.

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Which of the following situations best illustrates Newton's first law

kotykmax [81]

Newton's first law says that an object at rest will stay at rest, while an object in motion will stay in motion unless acted upon by an outside force.

A great example of this is a ball sitting on the ground. The ball will not move until some force is used on it, rather that be you kicking it, the wind blowing it, etc. Once that force is used against it, the ball will continue to move until gravity, air resistance, a friction bring it to a stop.

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4 years ago

A 4.50-kg wheel that is 34.5 cm in diametet rotates through an angle of 13.8 rad as it slows down uniformly from 22.0 rad/s to 1

lisabon 2012 [21]

Answer:

$\alpha =10.93radian/sec^2$

Explanation:

We have given given the final angular velocity $\omega _{final}=13.5rad/sec$

And $\omega _{initial}=22rad/sec$

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We have to find the angular acceleration $\alpha$

According to law of motion $\omega _{final}^2=\omega _{initial}^2+2\alpha \Theta$

So $13.5^2=22^2+2\times \alpha \times 13.8$

$\alpha =-10.93radian/sec^2$

In question we have tell about magnitude only so $\alpha =10.93radian/sec^2$

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3 years ago

PLEASE HELP!

Step2247 [10]

Answer:

A) 4n

Explanation:

He throws a snowball with a force of 4 N to the right, while the snowball pushes the person with a force of 4 N to the left. The given scenario is balanced because the same amount of force is acting in both direction.

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4 years ago

John says that the value of the function cos[ω(t + T) + ϕ], obtained one period T after time t, is greater than cos(ωt + ϕ) by 2

Svetllana [295]

Answer:

No one is right

Explanation:

John Case:

The function $cos(\omega t +\phi)$ is defined between -1 and 1, So it is not possible obtain a value $2\pi$ greater.

In addition, if you move the function cosine a T Value, and T is the Period, the function take the same value due to the cosine is a periodic function.

Larry case:

Is you have $f=1+cos(\omega t +\phi)$ , the domain of this is [0,2].

it is equivalent to adding 1 to the domain of the $f=1+cos(\omega t +\phi)$ , and its mean that the function $f=cos(\omega t +\phi)$ , in general, is not greater than $cos(\omega t +\phi)$ .

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3 years ago

A teacher explains that a scientist named Boyle did many experiments to determine what the relationship is between the volume an

lina2011 [118]

<span>Boyle's Law, because it describes what will happen in the relationship between the pressure and volume of the gas.</span>

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4 years ago