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konstantin123 [22]
3 years ago
13

Check

Physics
2 answers:
melamori03 [73]3 years ago
8 0

Answer:

the first one is neptune, second is saturn, thrid is uranus, and fourth is jupiter. just took the quiz ! hope this helps :)

Explanation:

Dmitriy789 [7]3 years ago
5 0

Answer:

the first one is: Neptune

second one: Saturn

third one: Uranus

fourth one: Jupiter

Explanation:

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Differences between single & double displacement reaction​
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<h2>Answer:</h2><h2>Single : A chemical reaction in which one element is replaced by another in a compound. </h2><h2>Double,:A chemical reaction involving the exchange of bonds between two non - reacting chemical species which results in the creation of products with similar bonding affiliations.</h2>

3 0
3 years ago
All simple machines are variations of which two basic machines?
SCORPION-xisa [38]
L<span>ever; inclined plane</span>
5 0
3 years ago
A rocket, initially at rest, is fired vertically with an upward acceleration of 10 m/s2. At an altitude of 0.50 km, the engine o
noname [10]

Answer:

The maximum altitude reached with respect to the ground = 0.5 + 0.510 = 1.01 km

Explanation:

Using the equations of motion,

When the rocket is fired from the ground,

u = initial velocity = 0 m/s (since it was initially at rest)

a = 10 m/s²

The engine cuts off at y = 0.5 km = 500 m

The velocity at that point = v

v² = u² + 2ay

v² = 0² + 2(10)(500) = 10000

v = 100 m/s

The velocity at this point is the initial velocity for the next phase of the motion

u = 100 m/s

v = final velocity = 0 m/s (at maximum height, velocity = 0)

y = vertical distance travelled after the engine shuts off beyond 0.5 km = ?

g = acceleration due to gravity = - 9.8 m/s²

v² = u² + 2gy

0 = 100² + 2(-9.8)(y)

- 19.6 y = - 10000

y = 510.2 m = 0.510 km

So, the maximum altitude reached with respect to the ground = 0.5 + 0.510 = 1.01 km

Hope this helps!!!

5 0
3 years ago
An objects momentum is determined by the object's
n200080 [17]
~Hello there! ^_^

Your question: An objects momentum is determined by the object's..?

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Happy Studying! =)




7 0
4 years ago
What is the electric field at a location b → = &lt;-0.5, -0.4, 0&gt; m, due to a particle with charge +2 nC located at the origi
Naddika [18.5K]

Answer:

E = \frac{8.99 x10^{9} \frac{Nm^2}{C^2} * 2x10^{-9} C}{(0.64m)^2} =43.85N

Explanation:

For this case we assume that we want to find the electrical field at the point P as we can see on the figure attached.

The electrical field wormula is given by:

E = \frac{K Q}{d^2}

Where r is the distance from the point and the charge. On this case we can use the Pythagoras theorem and we got:

d^2 = (-0.5m)^2 +(-0.4)^2 = 0.41m^2

d =\sqrt{0.41}= 0.64m

And now we can replace into the formula since we know that Q = 2nC= 2x10^{-9}C and K = 8.99 x10^{9} \frac{Nm^2}{C^2}, and we got:

E = \frac{8.99 x10^{9} \frac{Nm^2}{C^2} * 2x10^{-9} C}{(0.64m)^2} =43.85N

4 0
3 years ago
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