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Leni [432]
3 years ago
14

A graduate student is trying to follow the weather on Jupiter for her PhD thesis. To see the big weather patterns in the upper a

tmosphere of the planet, she needs to have excellent resolution. What type of telescope would be best for her to use? a. a refractor, with as small an aperture as possible b. a radio telescope c. a large reflector in an observatory located at sea level d. a large reflector located in orbit above the Earth's atmosphere e. you can't fool me, all these telescopes have the same resolution
Physics
1 answer:
DaniilM [7]3 years ago
5 0

Answer: large reflector located in orbit above the Earth's atmosphere

Explanation:

Since the student wants to see the big weather patterns in the upper atmosphere of the planet, and she will therefore need to have excellent resolution, the type of telescope that is ideal for her to use is a large reflector located in orbit above the Earth's atmosphere.

It should be noted that the refractor or a radio telescope isn't ideal in this situation as they will not capture the bug weather pattern and doesn't have an excellent resolution like the large reflector.

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A copper telephone wire has essentially
Lunna [17]

Answer:

128.21 m

Explanation:

The following data were obtained from the question:

Initial temperature (θ₁) = 4 °C

Final temperature (θ₂) = 43 °C

Change in length (ΔL) = 8.5 cm

Coefficient of linear expansion (α) = 17×10¯⁶ K¯¹)

Original length (L₁) =.?

The original length can be obtained as follow:

α = ΔL / L₁(θ₂ – θ₁)

17×10¯⁶ = 8.5 / L₁(43 – 4)

17×10¯⁶ = 8.5 / L₁(39)

17×10¯⁶ = 8.5 / 39L₁

Cross multiply

17×10¯⁶ × 39L₁ = 8.5

6.63×10¯⁴ L₁ = 8.5

Divide both side by 6.63×10¯⁴

L₁ = 8.5 / 6.63×10¯⁴

L₁ = 12820.51 cm

Finally, we shall convert 12820.51 cm to metre (m). This can be obtained as follow:

100 cm = 1 m

Therefore,

12820.51 cm = 12820.51 cm × 1 m / 100 cm

12820.51 cm = 128.21 m

Thus, the original length of the wire is 128.21 m

5 0
3 years ago
Calcium oxide write this in a formula
kykrilka [37]

The formula for calcium oxide is CaO.

4 0
3 years ago
A violin string vibrates at 260 Hz when unfingered. At what frequency will it vibrate if it is fingered one fourth of the way do
Advocard [28]

Answer:

346.66 Hz

Explanation:

l_1 = Length of string which is unfingered = l

l_2 = Length of string which is vibrate when fingered = l-\dfrac{1}{4}l=\dfrac{3}{4}l

f_1 = Unfingered frequency = 260 Hz

f_2 = Fingered frequency

Frequency is inversely proportional to length

f=\dfrac{1}{l}

So,

\dfrac{f_1}{f_2}=\dfrac{l_2}{l_1}\\\Rightarrow \dfrac{f_1}{f_2}=\dfrac{\dfrac{3}{4}l}{l}\\\Rightarrow \dfrac{f_1}{f_2}=\dfrac{3}{4}\\\Rightarrow f_2=\dfrac{4}{3}f_1\\\Rightarrow f_2=\dfrac{4}{3}260\\\Rightarrow f_2=346.66\ Hz

The frequency of the fingered string is 346.66 Hz

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the polluted urban environment affects the health and quality of life
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My mom and I walked 3,600 m in 90 minutes. What was our speed in m/min?
PtichkaEL [24]
Fill in the fraction: 3,600/90 = 40; turn it into a unit fraction.

40 mi/min
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