1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Leni [432]
3 years ago
14

A graduate student is trying to follow the weather on Jupiter for her PhD thesis. To see the big weather patterns in the upper a

tmosphere of the planet, she needs to have excellent resolution. What type of telescope would be best for her to use? a. a refractor, with as small an aperture as possible b. a radio telescope c. a large reflector in an observatory located at sea level d. a large reflector located in orbit above the Earth's atmosphere e. you can't fool me, all these telescopes have the same resolution
Physics
1 answer:
DaniilM [7]3 years ago
5 0

Answer: large reflector located in orbit above the Earth's atmosphere

Explanation:

Since the student wants to see the big weather patterns in the upper atmosphere of the planet, and she will therefore need to have excellent resolution, the type of telescope that is ideal for her to use is a large reflector located in orbit above the Earth's atmosphere.

It should be noted that the refractor or a radio telescope isn't ideal in this situation as they will not capture the bug weather pattern and doesn't have an excellent resolution like the large reflector.

You might be interested in
Because the moon rotates once for each revolution around Earth,
irina [24]
Good Morning, how are you?

Your answer is C. The moon orbits and rotates the same, so we NEVER see the far side of the moon from earth :)

Have a great day :)
7 0
2 years ago
Read 2 more answers
A girl playing tug-of-war with her dog pulls the dog a distance of 8.0m by exerting a force at an angle of 18° with the horizont
AnnZ [28]

Answer:

25 N

Explanation:

Work is a product of force and perpendicular distance moved.

W=Fd where F is force exerted and d is perpendicular distance.

However, for this case, the distance is inclined hence resolving it to perpendicular so that it be along x-axis we have distance as dcos\theta

Therefore, W=Fdcos\theta

Making F the subject of the formula then

F=\frac {W}{dcos\theta} where \theta is the angle of inclination. Substituting 190 J for W then 18 degrees for \theta and 8 m for d then

F=\frac {190}{8cos18^{\circ}}\approx 25N

3 0
2 years ago
A flute player hears four beats per second when she compares her note to a 523 HzHz tuning fork (the note C). She can match the
laiz [17]

Answer:

527 Hz

Solution:

As per the question:

Beat frequency of the player, \Delta f = 4\ beats/s

Frequency of the tuning fork, f = 523 Hz

Now,

The initial frequency can be calculated as:

\Delta f = f - f_{i}

f_{i} = f \pm \Delta f

when

f_{i} = f + \Delta f = 523 + 4 = 527 Hz

when

f_{i} = f - \Delta f = 523 - 4 = 519 Hz

But we know that as the length of the flute increases the frequency decreases

Hence, the initial frequency must be 527 Hz

7 0
3 years ago
Read 2 more answers
If the Earth and distant stars were stationary (motionless) in space, what would we observe about the wavelength from these star
dangina [55]
1) In the first case, the correct answer is
<span>A.Wavelengths measured would match the actual wavelengths emitted.
In fact, the stars are not moving relative to Earth, so there is no shift in the measured wavelength.

2) In this second case, the correct answer is
</span><span>A.Wavelengths measured would be shorter than the actual wavelengths emitted.
</span>in fact, since the stars in this case are moving towards the Earth, then apparent frequency of their emitted light will be larger than the actual frequency, because of the Doppler effect, according to the formula:
f'= \frac{c}{c+v_s} f_0
where f0 is the actual frequency, f' the apparent frequency, c the speed of light and vs the velocity of the source (the stars) relative to the obsever (Earth). Vs is negative when the source is moving towards the observer, so the apparent frequency f' is larger than the actual frequency f0. But the wavelength is inversely proportional to the frequency, so the apparent wavelength will be shorter than the actual wavelength.
6 0
2 years ago
An object with 5 protons, 5 electrons and 6 neutrons would have what charge
Anon25 [30]

Answer:

0

Explanation:

The object would be neutral. There are equal numbers of protons and electrons, so the positive and negative charges cancel one another.

5 0
3 years ago
Other questions:
  • Local environmental change have no effect on the global climate true or false
    9·1 answer
  • Describe some precautions needed to increase the safety of participants in the sports of football.
    7·1 answer
  • A backpack has a mass of 8 kg. It is lifted and given 54.9 J of gravitational potential energy. How high is it lifted? Accelerat
    14·2 answers
  • Zoning laws establish _______.
    14·1 answer
  • How would life be different for people in Basel Switzerland if they didn’t have the Rhine river
    11·1 answer
  • At 1:00 a.m., someone breaks a window in the back of a store and robs the safe. On the way out, the thief is cut on a piece of b
    14·1 answer
  • What is the gravity of sombrero galaxy compared to earth?
    5·2 answers
  • Organize these by 1 being the most and 16 being the least thing and by need if you were stranded on a deserted island
    11·2 answers
  • What is parabolic motion?​
    10·1 answer
  • Which is brighter in our sky, a star with apparent magnitude 2 or a star with apparent magnitude 7?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!