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Leni [432]
3 years ago
14

A graduate student is trying to follow the weather on Jupiter for her PhD thesis. To see the big weather patterns in the upper a

tmosphere of the planet, she needs to have excellent resolution. What type of telescope would be best for her to use? a. a refractor, with as small an aperture as possible b. a radio telescope c. a large reflector in an observatory located at sea level d. a large reflector located in orbit above the Earth's atmosphere e. you can't fool me, all these telescopes have the same resolution
Physics
1 answer:
DaniilM [7]3 years ago
5 0

Answer: large reflector located in orbit above the Earth's atmosphere

Explanation:

Since the student wants to see the big weather patterns in the upper atmosphere of the planet, and she will therefore need to have excellent resolution, the type of telescope that is ideal for her to use is a large reflector located in orbit above the Earth's atmosphere.

It should be noted that the refractor or a radio telescope isn't ideal in this situation as they will not capture the bug weather pattern and doesn't have an excellent resolution like the large reflector.

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Genrish500 [490]

Answer:

c

Explanation:

5 0
3 years ago
Can I put an “I” for an argumentative essay?
masha68 [24]

Answer:

There is no place for first person in formal academic argumentative essay. However, you can use first person only if it has been asked to provide your personal opinion or reflection about the topic.

Explanation:

4 0
3 years ago
To study the properties of various particles, you can accelerate the particles with electric fields. A positron is a particle wi
Gnom [1K]

Answer:

(a) Acceleration of positron is 6.03 x 10¹³ m/s²

(b) Speed of positron after 8.70 x 10⁻⁹ s is 5.24 x 10⁵ m/s

Explanation:

Given :

Constant electric field, E = 343 N/C

Mass of positron, m = 9.1 x 10⁻³¹ kg

Charge of positron, q = +e = 1.6 x 10⁻¹⁹ C

(a) Coulomb force on the positron is determine by the relation :

F = q x E    ....(1)

But, force is also equals to product of mass and acceleration. So,

F = ma  .....(2)

Here a is acceleration.

From equation (1) and (2).

m x a = q x E

a=\frac{qE}{m}

Substitute the values of q, E and m in the above equation.

a=\frac{1.6\times10^{-19}\times 343}{9.1\times10^{-31} }

a = 6.03 x 10¹³ m/s²

(b) Initially, the positron is at rest, so its initial speed is zero.

The equation of motion for positron is :

v = u + at

Here v is final speed, u is initial speed and t is time.

Since, u is zero, so the equation becomes :

v = at

Substitute 8.70 x 10⁻⁹ s for t and 6.03 x 10¹³ m/s² for a in the above equation.

v = 6.03 x 10¹³ x 8.70 x 10⁻⁹ m/s

v = 5.24 x 10⁵ m/s

 

6 0
3 years ago
An 850 kg elevator is accelerating upwards at 3.0 m/s2. Calculate the tension in the cable.
sveta [45]

Answer:

10880N

Explanation:

We are given that

Mass of elevator, m=850 kg

Acceleration, a=3m/s^2

g=9.8m/s^2

We have to find the tension in the cable.

We know that

When elevator is accelerating upward then tension in the cable

T=m(a+g)

Using the formula

T=850(3+9.8)

T=10880N

7 0
3 years ago
Please I really need help, I will mark you brainliest
Artemon [7]

Explanation:

I am not sure about this question sry but u can try asking a tutor u don't need to use any points

5 0
3 years ago
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