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a sealed container filled with argon gas at 35 c has a pressure of 832 torr. if the volume of the container is decreased by a fa

lesya692 [45]

Answer:

If the volume of the container is decreased by a factor of 2 the pressure is is increased by the same factor to 1664 torr.

Explanation:

Here we have Boyle's law which states that, at constant temperature, the volume of a given mass of gas is inversely proportional to its pressure

V ∝ 1/P or V₁·P₁ = V₂·P₂

Where:

V₁ = Initial volume

V₂ = Final volume = V₁/2

P₁ = Initial pressure = 832 torr

P₂ = Final pressure = Required

From V₁·P₁ = V₂·P₂ we have,

P₂ = V₁·P₁/V₂ = V₁·P₁/(V₁/2)

P₂ = 2·V₁·P₁/V₁ = 2·P₁ = 2× 832 torr = 1664 torr

6 0

3 years ago

Read 2 more answers

Do the alkali metals tend to gain or lose electrons in chemical reactions?

timofeeve [1]

Noble Gases more often than not don't respond on the grounds that they don't tend to pick up or lose electrons. Salt and Alkaline Earth Metals are delicate and soften at low temperatures. Incandescent lamp are extremely receptive nonmetals since they effortlessly acknowledge electrons from different components.

6 0

3 years ago

An analytical chemist is titrating 242.5mL of a 1.200M solution of hydrazoic acid HN3 with a 0.3400M solution of NaOH . The pKa

fgiga [73]

Answer: The pH of the solution is 12.61

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}$ ......(1)

For hydrazoic acid:

Molarity of hydrazoic acid solution = 1.200 M

Volume of solution = 242.5 mL

Putting values in equation 1, we get:

$1.200M=\frac{\text{Moles of hydrazoic acid}\times 1000}{242.5mL}\\\\\text{Moles of hydrazoic acid}=0.291mol$

For NaOH:

Molarity of NaOH solution = 0.3400 M

Volume of solution = 1006 mL

Putting values in equation 1, we get:

$0.3400M=\frac{\text{Moles of NaOH}\times 1000}{1006mL}\\\\\text{Moles of NaOH}=0.342mol$

The chemical reaction for hydrazoic acid and NaOH follows the equation:

$HN_3+NaOH\rightarrow NaN_3+H_2O$

Initial: 0.291 0.342

Final: 0 0.051 0.291 0.291

Volume of solution = 242.5 + 1006 = 1248.5 mL = 1.2485 L (Conversion factor: 1 L = 1000 mL)

For NaOH left:

Left moles of NaOH = 0.051 moles

Volume of the solution = 1.2485 L

Putting values in equation 1, we get:

$\text{Molarity of NaOH}=\frac{0.051mol}{1.2485L}=0.0408M$

1 mole of NaOH produces 1 mole of sodium ions and 1 mole of hydroxide ions

To calculate pOH of the solution, we use the equation:

$pOH=-\log[OH^-]$

We are given:

$[OH^-]=0.0408M$

Putting values in above equation, we get:

$pOH=-\log(0.0408)\\\\pOH=1.39$

To calculate pH of the solution, we use the equation:

$pH+pOH=14\\\\pH=14-1.39=12.61$

Hence, the pH of the solution is 12.61

8 0

3 years ago

Chemistry help!! I'll give 30 points!!!

malfutka [58]

1. 1/16 x 1 000 000= 62500
2. Each half life is 5750 years long
3. The end of a half life is found by dividing the beginning of the half life by 2.
4. The number 62500 is between the 7th and the 8th half lives (refer to the number of 14C atoms on my table)
5. The 7th half life is 40250 years, and the 8th half life is 46000 years.
6. Therefore, your estimate would be a number roughly in the middle of 40250 and 46000 (for example: 43000)
Hope this helps :)