Answer:
Explanation:
Weight of the dye in solution 1 = 0.2653 g in 100 mL
Weight of the dye in solution 2 = 0.02653 g in 100 mL
Weight of the dye in solution 1 = 0.0013265 g in 100 mL
The percentage concentration can be calculated by using the formula :
percentage concentration = (weight of the substance / volume of the solution) × 100
For Solution (1)
percentage concentration = (0.2653 /100) × 100
percentage concentration = 0.2653%
percentage concentration = 0.267 % (to significant figure)
For solution (2)
percentage concentration = (0.02653 /100) × 100
percentage concentration = 0.02653%
percentage concentration = 0.0267 % (to significant figure)
For the final percentage concentration for Solution (3)
percentage concentration = (0.0013265 /100) × 100
percentage concentration = 0.0013265%
percentage concentration = 0.0013 % (to significant figure)
The mg/L for solution (1) is:
= 265.3 mg/0.1 L
= 2653 mg/L
The mg/L for solution (2) is:
= 26.53 mg/0.1 L
= 265.3 mg/L
The mg/L for solution (3) is:
= 1.3265 mg/0.1 L
= 13.265 mg/L
Molarity = (given weight/molecular weight) × (volume of the solution in L / 1.0 L)
For solution (1):
Molarity = (0.2653 / 879.9) × (0.1 L /1 L)
= 3.128×10⁻⁵ M
For solution (2)
Molarity = (0.02653 / 879.9) × (0.1 L / 1 L)
= 3.015×10⁻⁶ M
For solution (3)
Molarity = (0.0013265 / 879.9) × (0.1 L / 1 L)
= 1.508×10⁻⁷M
