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viva [34]
3 years ago
6

Choose the number of significant figures indicated. 90

Chemistry
2 answers:
Verizon [17]3 years ago
8 0

There are 2 significant figures. Hope this helps :)

kvv77 [185]3 years ago
3 0
There are 2 significant figures. All numbers in a whole number are significant.
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When 85 L of gas at 1.376 atm has its pressure changed to 0.154 atm, what is the new volume?
igor_vitrenko [27]

Answer:

<h2>759.48 L</h2>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the new volume

V_2 =  \frac{P_1V_1}{P_2}  \\

From the question we have

V_2 =  \frac{85 \times 1.376}{0.154}  =  \frac{116.96}{0.154}  \\  = 759.480519...

We have the final answer as

<h3>759.48 L</h3>

Hope this helps you

4 0
3 years ago
Which type of bonding is characterized by overlapping orbitals that allow outer electrons of atoms to move about freely througho
Sonja [21]

Answer:

D metallic

Explanation:

The chemical bonding which rises from electrostatic attractive force between the conduction electrons and the positively charged metal ions is called metallic bonding.

<u>It is sharing of the free electrons among the structure of the positively charged ions which are known as cations. </u>

<u>In this type of bonding, these free electrons freely move in the crystal mattice of the metal.  </u>

The bonding accounts for properties of metals, such as ductility, strength,  electrical and thermal conductivity and resistivity and luster.

6 0
3 years ago
Equation balancing a. S(s) + O2(g) → SO3(8) b. 2Al(s) + 3C12(8) ► 2AICI,(s) E. 2NaOH(s) + H2SO,(ac) —Na,SO (ac) + H2O(1) d. CHg(
Debora [2.8K]

Answer:

a. S(s) + 3/2 O₂(g) → SO₃(g)

b. Al(s) + 3/2 Cl₂(g) → AICI₃(s)

c. 2 NaOH(s) + H₂SO₄(ac) → Na₂SO₄(ac) + 2 H₂O(l)

d. C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) +  4 H₂O(g)

Explanation:

We will balance the equation using the trial and error method.

a. S(s) + O₂(g) → SO₃(g)

1. We will balance O atoms by multiplying O₂by 3/2.

S(s) + 3/2 O₂(g) → SO₃(g)

b. Al(s) + Cl₂(g) → AICI₃(s)

1. We will balance Cl atoms by multiplying Cl₂ by 3/2.

Al(s) + 3/2 Cl₂(g) → AICI₃(s)

c. NaOH(s) + H₂SO₄(ac) → Na₂SO₄(ac) + H₂O(l)

1. We will balance Na atoms by multiplying NaOH by 2.

2. We will balance H and O atoms by multiplying H₂O by 2.

2 NaOH(s) + H₂SO₄(ac) → Na₂SO₄(ac) + 2 H₂O(l)

d. C₃H₈(g) + O₂(g) → CO₂(g) +  H₂O(g)

1. We will balance C atoms by multiplying CO₂ by 3.

2. We will balance H atoms by multiplying H₂O by 4.

3. We will balance O atoms by multiplying O₂ by 5.

C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) +  4 H₂O(g)

8 0
3 years ago
What are the relative ion concentrations in an acid solution?
Veronika [31]
Answer is: more H⁺ ions than OH⁻ ions.
<span>An Arrhenius acid is a substance that dissociates in water to form hydrogen ions or protons. 
For example, hydrochloric acid dissociate in aqueous solution to form hydrogen ions (H</span>⁺) and chloride anion (Cl⁻):<span>
HCl(aq) → H</span>⁺(aq) + Cl⁻<span>(aq).
</span>

An Arrhenius base is a substance that dissociates in water to form hydroxide ions (OH⁻<span>). 
For example lithium hydroxide is an Arrhenius base:</span>

LiOH(aq) → Li⁺(aq) + OH⁻(aq).


4 0
3 years ago
A sample of argon (Ar) gas has a volume of 7.31 L at a pressure of
Pie

Answer:

17.1 L

Explanation:

P1V1/T1  =  P2V2/T2        T is in K

P1V1/T1 * T2/P2 = V2

735 * 7.31 / (45+273.15)  * (55+ 273.15)/325 = V2

V2 = 17.1 L

3 0
2 years ago
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