Answer:
The average power provided by the tension in the cable pulling the lift is = 714 W
Explanation:
Given data
Mass = 71 kg
Change in height = 123 m
When the lift moves in upward direction then in that case kinetic energy is constant & only potential energy changes.
Change in potential energy Δ PE = m g ( 
)
Δ PE = 71 × 9.81 × 123
Δ PE = 85670.73 J
Time = 2 min = 120 sec
So average power is given by
Therefore the average power provided by the tension in the cable pulling the lift is = 714 W
Force = mass · acceleration
Given that force equals 13.4N and acceleration is 7.9m/s/s, simply plug in those values to solve for mass.
M = F/A = 13.4N/7.9m/s/s = 1.696kg
Answer:
The angular momentum of the system is 0.18kgm²/s
Explanation:
L = angular momentum of the particle 1 + angular momentum of the particle 2
L = ml²ω + ml²ω
L = 2ml²ω
Given that,
m = 500g are connected by a massless cord
=0.500kg
l = 30cm
= 0.30m
angular speed ω = 2.0 rev/s
angular momentum of the system =
L = 2ml²ω
L = 2 × 0.500 × (0.30)² × 2
L = 2 × 0.500 × 0.09 × 2
L = 0.18kgm²/s
Thus, the angular momentum of the system is 0.18kgm²/s
Answer:
here is the answer
Explanation:
initial velocity= u= 0
final velocity = v
acceleration= 1.30m/s²
time= 6 seconds
using formula
a = v-u/t
1.30 = v - 0/6
1.30*6 = v - 0
7.8= v - 0
7.8 = v
therefore, final velocity is 7.8 m/s
