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Anna71 [15]
3 years ago
5

A uniform magnetic field is perpendicular to the plane of a wire loop. If the loop accelerates in the direction of the field, wi

ll a current be induced in the loop? Explain why or why not.
Physics
1 answer:
Nataly [62]3 years ago
3 0

Answer:

No

Explanation:

If the coil is accelerated parallel to the magnetic field, it means also that the force on the coil acts parallel to the field. For current to be induced in a coil, a basic condition must be met which is that the directions of force (acceleration) and the magnetic field must be perpendicular to each other. This brings about current being induced in a direction perpendicular to bothering the directions of the force acting on the coil and the that of the magnetic field. This current would flow through the coil in either a clockwise or anticlockwise manner.

Since the coil is accelerated parallel to the magnetic field, no current is induced in it.

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What is the formula for finding your maximum heart rate
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5 0
3 years ago
In a double-slit experiment, the third-order maximum for light of wavelength 510 nm is located 17 mm from the central bright spo
Marysya12 [62]

Answer:

14.9 mm

Explanation:

We know dsinθ = mλ where d = separating of slit, m = order of maximum = 3 and λ = wavelength = 510nm = 510 × 10⁻⁹ m

Also tanθ = L/D where L = distance of m order fringe from central bright spot = 17 mm = 0.017 m and D = distance of screen from slit = 1.6 m

So, sinθ = mλ/d

Since θ is small, sinθ ≅ tanθ

So,

mλ/d = L/D

d = mλD/L

Substituting the values of the variables into the equation, we have

d = 3 × 510 × 10⁻⁹ m × 1.6 m/0.017 m

d = 2448 × 10⁻⁹ m²/0.017 m

d = 144000 × 10⁻⁹ m

d = 1.44 × 10⁻⁴ m

d = 0.144 × 10⁻³ m

d = 0.144 mm

Now, for the second-order maximum, m' of the 670 nm wavelength of light,

m'λ'/d = L'/D where m' = order of maximum = 2, λ' = wavelength of light = 670 nm = 670 × 10⁻⁹ m, d = slit separation = 0.144 mm = 0.144 × 10⁻³ m, L' = distance of second order maximum from central bright spot and D = distance of screen from slit = 1.6m

So, L' = m'λ'D/d

So, substituting the values of the variables into the equation, we have

L' = 2 × 670 × 10⁻⁹ m × 1.6 m/0.144 × 10⁻³ m

L' = 2144  × 10⁻⁹ m²/0.144 × 10⁻³ m

L' = 14888.89 × 10⁻⁶ m

L' = 0.01488 m

L' ≅ 0.0149 m

L' = 14.9 mm

4 0
3 years ago
A solenoid of length 8.50 cm and diameter 0.840 cm is wound with 339 turns per centimeter. If the current in the solenoid is dec
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Answer:

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Explanation:

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6 0
3 years ago
Read 2 more answers
A small mirror is attached to a vertical wall, and it hangs a distance of 1.87 m above the floor. The mirror is facing due east,
Oksana_A [137]

Answer:

 t = 1.62 h

Explanation:

A flat mirror fulfills the law of reflection where the incident angle is equal to the reflected angle.

          θ_i = θ_r

If we use trigonometry to find the angles, the mirror is at a height of L = 1.87 m,   and the reflected rays reach a distance x1 = 3.56 m

         tan θ₁ = x₁ / L

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         θ₁ = tan⁻¹  1.90

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for the second case x₂ = 1.46 m

        tan θ₂ = x₂ / L

        θ₂ = tan⁻¹  \frac{1.46}{1.87}

        θ₂ = 37.98º

the difference in degree traveled is

         Δθ = θ₁- θ₂

          Δθ = 62.29 - 37.98

          Δθ = 24.31º

as in the exercise they indicate that every 15º there is an hour

         t = 24.31º (1h / 15º)

         t = 1.62 h

4 0
3 years ago
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