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mr_godi [17]
3 years ago
7

A bubble of helium gas has a volume of 0.65 L near the bottom of a large

Chemistry
1 answer:
Flura [38]3 years ago
8 0

Answer:

0.73L

Explanation:

The following data were obtained from the question :

V1 = 0.65 L

P1 = 3.4 atm

T1 = 19°C = 19 + 273 = 292K

V2 =?

P2 = 3.2 atm

T2 = 36°C = 36 + 273 = 309K

The bubble's volume near the top can be obtain as follows:

P1V1 /T1 = P2V2 /T2

3.4 x 0.65/292 = 3.2 x V2 /309

Cross multiply to express in linear form as shown below:

292 x 3.2 x V2 = 3.4 x 0.65 x 309

Divide both side by 292 x 3.2

V2 = (3.4 x 0.65 x 309) /(292 x 3.2)

V2 = 0.73L

Therefore, the bubble's volume near the top is 0.73L

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Answer:

The correct answer is B.

Explanation:

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The ratio of masses are given as:

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The law states that 'the elements combining to form compound always combine in a fixed ratio by their mass.'

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3 years ago
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OLga [1]
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5 0
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Type the correct answer in the box. Express your answer to three significant figures. This balanced equation shows the reaction
Ratling [72]

Answer:

514.5 g.

Explanation:

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  • Since NaOH is in excess, so H₂SO₄  is the limiting reactant.
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n of H₂SO₄ = mass/molar mass = (355.0 g)/(98.0 g/mol) = 3.622 mol.

Using cross multiplication:

∵ 1.0 mol H₂SO₄ produces → 1.0 mol of Na₂SO₄.

∴ 3.622 mol H₂SO₄ produces → 3.662 mol of Na₂SO₄.

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3 years ago
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Arte-miy333 [17]

Answer:

Explanation:

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Answer:

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