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2 years ago

Quantitative was to measure light intensity

2 answers:

7 0

One candela per steradian is termed a lumen, which is the measure of light intensity people are most familiar with One foot candle is equivalent to one lumen per square foot

Norma-Jean [14]2 years ago

3 0

Whats the question tho??

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1. What is the relation between distance and speed?

Inga [223]

Answer:

option no b is right answer

6 0

3 years ago

How many electrons would be found in an isotope of silicon 29

kenny6666 [7]

14 electrons15 neutrons

5 0

3 years ago

How many grams of oxygen are required to burn 60 grams of ethane gas, C2H6? 2 C2H6 (g) + 7 O2(g) → 4 CO2 (g) + 6 H2O (g)

timofeeve [1]

60 g C2H6 × 1 mol C2H6 x 7 mol O2 x 32 g O2 = ~223.5 g O2
30.068 g 2 mol C2H6 1 mol O2

8 0

3 years ago

How many grams of NO can be produced if 204 g of NO2 is mixed with 58.1 g of H2O?

Goshia [24]

Answer:

44.4 grams of NO can be produced

Explanation:

Step 1: Data given

Mass of NO2 = 204 grams

Molar mass NO2 = 46.0 g/mol

Mass of H2O = 58.1 grams

Molar mass H2O = 18.02 g/mol

Step 2: The balanced equation

3NO2 + H2O→ 2HNO3 + NO

Step 3: Calculate moles NO2

Moles NO2 = 204 grams / 46.0 g/mol

Moles NO2 = 4.43 moles

Step 4: Calculate moles H2O

Moles H2O = 58.1 grams / 18.02 g/mol

Moles H2O = 3.22 moles

Step 5: Calculate limiting reactant

For 3 moles NO2 we need 1 mol H2O to produce 2 moles HNO3 and 1 mol NO

NO2 is the limiting reactant. It will completely be consumed (4.43 moles). H2O is in excess. there will react 4.43 /3 = 1.48 moles. There will remain 3.22 - 1.48 = 1.74 moles

Step 6: Calculate moles NO

For 3 moles NO2 we need 1 mol H2O to produce 2 moles HNO3 and 1 mol NO

For 4.43 moles NO2 we'll have 4.43/3 = 1.48 moles NO

Step 7: Calculate mass NO

Mass NO = 1.48 moles * 30.01 g/mol

Mass NO = 44.4 grams

44.4 grams of NO can be produced

3 0

3 years ago

Calculate the [H+]

ELEN [110]

[H⁺]=6.696 x 10⁻⁵

pH = 4.174

<h3> Further explanation </h3>

Given

The concentration of 0.000295 M (2.95 x 10⁻⁴ M) butanoic acid solution

Required

the [H+] and pH

Solution

Butanoic acid is the carboxylic acid group. Carboxylic acids are weak acids

For weak acid :

$\tt [H^+]=\sqrt{Ka.M}$

Input the value :

[H⁺]=√1.52 x 10⁻⁵ x 2.95 x 10⁻⁴

[H⁺]=6.696 x 10⁻⁵

pH = - log [H⁺]

pH = - log 6.696 x 10⁻⁵

pH = 5 - log 6.696

pH = 4.174

5 0

3 years ago