The frequency of the oscillation in hertz is calculated to be 0.00031 Hz.
The frequency of a wave is defined as the number of cycles completed per second while the period refers to the time taken to complete a cycle. The frequency is the inverse of period.
So;
Period(T) = 54 minutes or 3240 seconds
Frequency (f) = T-1 = 1/T = 1/3240 seconds = 0.00031 Hz
Learn more: brainly.com/question/14588679
Answer:
1÷60 h
time equals distance upon speed
Answer:
The energy that the truck lose to air resistance per hour is 87.47MJ
Explanation:
To solve this exercise it is necessary to compile the concepts of kinetic energy because of the drag force given in aerodynamic bodies. According to the theory we know that the drag force is defined by

Our values are:




Replacing,


We need calculate now the energy lost through a time T, then,

But we know that d is equal to

Where
v is the velocity and t the time. However the time is given in seconds but for this problem we need the time in hours, so,

(per hour)
Therefore the energy that the truck lose to air resistance per hour is 87.47MJ
Complete Question
The complete question is shown on the first uploaded image
Compare the percent error between your value and the accepted value of 1.26 times 10-6 T · m/A. (Use the accepted value given to three significant figures in your calculation.). 100% % error = %
Answer:
The permeability of free space is 
The percentage error is % error = 5.25%
Explanation:
From the question we are told that
The slope is
, and
Generally 
So 
From the relation given in the question
![\mu_0 = \frac{2R}{N} [\frac{B}{I} ]](https://tex.z-dn.net/?f=%5Cmu_0%20%3D%20%5Cfrac%7B2R%7D%7BN%7D%20%5B%5Cfrac%7BB%7D%7BI%7D%20%5D)
Where R is the radius of the coil 
N is the number of loops of the coil = 10
Now from the question we are told that

substituting into the equation above

Substituting values


Generally the % error is mathematically represented as
%
Given that the accepted value is
Hence substituting values
%

First harmonic of a closed pipe is determined as velocity, v, to four times length (4L), F₀ v/4L.
<h3>
First harmonic of a closed pipe</h3>
The first harmonic of a closed pipe is the fundamental frequency of the closed of the closed pipe.
L = λ/4
where;
- L is the length of the pipe
- λ is the wavelength of sound
λ = 4L
But, v = F₀λ
v = F₀(4L)
F₀ = v/4L
where;
- F₀ is the first harmonic
- v is speed of sound
Thus, first harmonic of a closed pipe is determined as velocity, v, to four times length (4L), F₀ v/4L.
Learn more about fundamental frequency here: brainly.com/question/1967686
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