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2 years ago

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Which formula represents final velocity of an object with average acceleration?

2 answers:

zheka24 [161]2 years ago

5 0

Answer:

The equation v – = v 0 + v 2 v – = v 0 + v 2 is reflects the fact that when acceleration is constant, v – is just the simple average of the initial and final velocities.

Explanation:

hope this is it

Dmitry_Shevchenko [17]2 years ago

3 0

Explanation:

the equation v-=v0+v2-v-=v0+v2 is reflects the fact that when acceleration is constant,v- is just the simple areragevof the initial and final velocities

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804 n of force are applied to a 51.7 kg. What is the acceleration that the object experiences?

Andreyy89

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This means, in this case there would be no friction and absolutely no other force which gives a component in the plane of motion, only then can you assume that F=804N.

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804 = 51.7*a

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A stone is dropped into a well. The sound of the splash is heard 3.5 seconds later. What is the depth of the well? Take the spee

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Answer:

The depth of the well, s = 54.66 m

Given:

time, t = 3.5 s

speed of sound in air, v = 343 m/s

Solution:

By using second equation of motion for the distance traveled by the stone when dropped into a well:

$s = ut +\frac{1}{2}at^{2}$

Since, the stone is dropped, its initial velocity, u = 0 m/s

and acceleration is due to gravity only, the above eqn can be written as:

$s = \frac{1}{2}gt'^{2}$

$s = \frac{1}{2}9.8t^{2} = 4.9t'^{2}$ (1)

Now, when the sound inside the well travels back, the distance covered,s is given by:

$s = v\times t''$

$s = 343\times t''$ (2)

Now, total time taken by the sound to travel:

t = t' + t''

t'' = 3.5 - t' (3)

Using eqn (2) and (3):

s = 343(3.5 - t') (4)

from eqn (1) and (4):

$4.9t'^{2} = 343(3.5 - t')$

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t' = 3.34 s

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