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lawyer [7]
3 years ago
6

The table below shows data of sprints of animals that traveled 75 meters. At each distance marker, the animals' times were recor

ded. Which animal moves with accelerated motion?
Time at Distance Markers
Animal 25 meters 50 meters 75 meters
Animal 1 3 seconds 5 seconds 6 seconds
Animal 2 4 seconds 8 seconds 12 seconds
Animal 3 3 seconds 6 seconds 9 seconds
Animal 4 10 seconds 20 seconds 30 seconds
Animal 1
Animal 2
Animal 3
Animal 4
Physics
1 answer:
emmainna [20.7K]3 years ago
6 0

Answer:

Animal 1

Explanation:

For an animal moving with uniform motion ( = constant speed, no acceleration), the distance covered in equal time intervals is always the same.

From the table, we can see that this situation occurs for animal 2, animal 3 and animal 4. In fact, for all these 3 animals, the time interval to cover each block of 25 meters remains constant; in particular:

- Animal 2 always takes 4 seconds to cover each 25 m block

- Animal 3 always takes 3 seconds to cover each 25 m block

- Animal 4 always takes 10 seconds to cover each 25 m block

The situation is different for animal 1; in fact:

- it takes 3 seconds to cover the first 25 m

- it takes (5-3)=2 seconds to cover the second block of 25 m

- it takes (6-5)=1 seconds to cover the third block of 25 m

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DiKsa [7]

Answer:

a.\rm -1.49\ m/s^2.

b. \rm 50.49\ m.

Explanation:

<u>Given:</u>

  • Velocity of the particle, v(t) = 3 cos(mt) = 3 cos (0.5t) .

<h2>(a):</h2>

The acceleration of the particle at a time is defined as the rate of change of velocity of the particle at that time.

\rm a = \dfrac{dv}{dt}\\=\dfrac{d}{dt}(3\cos(0.5\ t ))\\=3(-0.5\sin(0.5\ t.))\\=-1.5\sin(0.5\ t).

At time t = 3 seconds,

\rm a=-1.5\sin(0.5\times 3)=-1.49\ m/s^2.

<u>Note</u>:<em> The arguments of the sine is calculated in unit of radian and not in degree.</em>

<h2>(b):</h2>

The velocity of the particle at some is defined as the rate of change of the position of the particle.

\rm v = \dfrac{dr}{dt}.\\\therefore dr = vdt\Rightarrow \int dr=\int v\ dt.

For the time interval of 2 seconds,

\rm \int\limits^2_0 dr=\int\limits^2_0 v\ dt\\r(t=2)-r(t=0)=\int\limits^2_0 3\cos(0.5\ t)\ dt

The term of the left is the displacement of the particle in time interval of 2 seconds, therefore,

\Delta r=3\ \left (\dfrac{\sin(0.5\ t)}{0.05} \right )\limits^2_0\\=3\ \left (\dfrac{\sin(0.5\times 2)-sin(0.5\times 0)}{0.05} \right )\\=3\ \left (\dfrac{\sin(1.0)}{0.05} \right )\\=50.49\ m.

It is the displacement of the particle in 2 seconds.

7 0
3 years ago
All fires require oxygen () There is no oxygen in that room (T) .
Marina CMI [18]

The sentences are invalid and unsound.

<h3><u>Explanation</u>:</h3>

The fire is defined as the vigorous oxidation of a substance. Now oxidation can occur in presence of any oxidising agent. Like magnesium in presence of nitrogen in high temperature with a dazzling brownish flame to produce magnesium nitride. So fire can be produced in absence of oxygen.

Oxygen is present everywhere in world. So production of a whole room without oxygen is very tough to produce and costly process. So its very unsound.

4 0
3 years ago
2. A 50 kg diver is standing on the edge of a 15 m high cliff. What is his potential energy?
Lera25 [3.4K]

Answer:

3675 J

Explanation:

Gravitational Potential Energy = \frac{1}{2} × mass × g × height

( g is the gravitation field strength )

Mass = 50 kg

G = 9.8 N/kg ( this is always the same )

Height = 15 m

Gravitational Potential Energy = \frac{1}{2} × 50 ×9.8 × 15

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3 0
3 years ago
Use Newton’s Universal Law of Gravitation to calculate the magnitude of the gravitational force between a 200 kg refrigerator an
expeople1 [14]

Answer:

3.735×10⁻⁶ N

Explanation:

From newton' s law of universal gravitation,

F = Gmm'/r² .............................. Equation 1

Where F = Gravitational force between the person and the refrigerator, m = mass of the person, m' = mass of the refrigerator, r = distance between the person and the refrigerator. G = gravitational universal constant.

Given: m = 70 kg, m' = 200 kg, r = 0.5 m

Constant: G = 6.67×10⁻¹¹ Nm²/kg².

F = (6.67×10⁻¹¹×70×200)/0.5²

F = 93380×10⁻¹¹/0.25

F = 373520×10⁻¹¹

F = 3.735×10⁻⁶ N

Hence the force between the person and the refrigerator =  3.735×10⁻⁶ N

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psychologist counseling would be the correct answer I believe

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