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lawyer [7]
3 years ago
6

The table below shows data of sprints of animals that traveled 75 meters. At each distance marker, the animals' times were recor

ded. Which animal moves with accelerated motion?
Time at Distance Markers
Animal 25 meters 50 meters 75 meters
Animal 1 3 seconds 5 seconds 6 seconds
Animal 2 4 seconds 8 seconds 12 seconds
Animal 3 3 seconds 6 seconds 9 seconds
Animal 4 10 seconds 20 seconds 30 seconds
Animal 1
Animal 2
Animal 3
Animal 4
Physics
1 answer:
emmainna [20.7K]3 years ago
6 0

Answer:

Animal 1

Explanation:

For an animal moving with uniform motion ( = constant speed, no acceleration), the distance covered in equal time intervals is always the same.

From the table, we can see that this situation occurs for animal 2, animal 3 and animal 4. In fact, for all these 3 animals, the time interval to cover each block of 25 meters remains constant; in particular:

- Animal 2 always takes 4 seconds to cover each 25 m block

- Animal 3 always takes 3 seconds to cover each 25 m block

- Animal 4 always takes 10 seconds to cover each 25 m block

The situation is different for animal 1; in fact:

- it takes 3 seconds to cover the first 25 m

- it takes (5-3)=2 seconds to cover the second block of 25 m

- it takes (6-5)=1 seconds to cover the third block of 25 m

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a car is moving 8.80 m/s when it begins to accelerate at 2.45 m/s^2. how much time does it take to trav 138m. please help me (':
Ulleksa [173]

Answer:

7.6 s

Explanation:

Considering kinematics formula for final velocity as

v^{2}=u^{2}+2as

Where v and u are final and initial velocities, a is acceleration and s is distance moved.

Making v the subject then

v=\sqrt{u^{2}+2as}

Substituting 8.8 m/s for u, 138 m for s and 2.45 m/s2 for a then

v=\sqrt{8.8^{2}+2*2.45*138}\\v=27.45 m/s

Also, v=u+at and making t the subject of the formula

t=\frac {v-u}{a}

Substituting 27.45 m/s for v, 8.8 m/s for u and 2.45 m/s for a then

t=\frac {27.45-8.8}{2.45}=7.6122448979591\approx 7.6s

Therefore, it needs 7.6 seconds to travel

7 0
3 years ago
Six identical resistors are connected in series with a battery. The number of joules per second supplied by the battery is then
Nataly_w [17]

Answer:

The option (b) is correct.

Explanation:

The expression for the power in terms of work done is as follows;

P=\frac{W}{t}

Here, W is the work done, t is the time taken and P is the power.

According to the given problem, six identical resistors are connected in series with a battery. The number of joules per second supplied by the battery is then determined.

The expression for the equivalent resistance in the series combination is as follows;

R_{eq}=R_{1}+R_{2}......+R_{6}

Put R_{1},R_{2}......,R_{6}=R.

R_{eq}=R+R+R+R+R+R

R_{eq}=6R

It is given in the problem that a seventh resistor is added (in series).

R_{eq}=R_{1}+R_{2}......+R_{7}

Put R_{1},R_{2}......,R_{7}=R.

R_{eq}=R+R+R+R+R+R+R

R_{eq}=7R

The expression for the power in terms of voltage and resistance is as follows;

P=\frac{V^{2}}{R}

Here, R is the resistance.

From the above expression, it can be concluded that the power, the number of joules per second supplied by the battery is inversely proportional to the resistance. The equivalent resistance increases if the seventh resistance is connected with a battery.

If a seventh resistor is added (in series) the number of joules per second supplied by the battery decreases.

Therefore, the option (b) is correct.

5 0
3 years ago
If velocity is in m/s and time is in sec, what is the unit of acceleration?​
WINSTONCH [101]
The unit of acceleration would be m/s² :)
6 0
2 years ago
A 5.0 cm object is 12.0 cm from a concave mirror that has a focal length of 24.0 cm. The distance between the image and the mirr
MA_775_DIABLO [31]

Answer:

The answer is 24cm

Explanation:

This problem bothers on the curved mirrors, a concave type

Given data

Object height h= 5cm

Object distance = 12cm

Focal length f=24cm

Let the image distance be v=?

Applying the formula we have

1/v +1/u= 1/f

Substituting our given data

1/v+1/12=1/24

1/v=1/24-1/12

1/v=1-2/24

1/v=-1/24

v= - 24cm

This implies that the image is on the same side as the object and it is real

7 0
3 years ago
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BARSIC [14]
The correct answer is C
5 0
3 years ago
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