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Butoxors [25]
3 years ago
12

A 193nm-wavelength UV laser for eye surgery emits a 0.500mJ pulse. (a) How many photons does the light pulse contain?

Physics
2 answers:
Law Incorporation [45]3 years ago
6 0

Answer:

The number of photons is 4.8x10^14

Explanation:

The frequency of wave is equal to:

f=\frac{c}{l}

where c is the speed of light, l is the wavelength of wave. Replacing values:

f=\frac{3x10^{8} }{193x10^{9} } =1.5x10^{15} Hz

The energy of the proton is:

E=hf

where h is the Planck´s constant. Replacing

E=6.626x10^{-34}*1.5x10^{5}=1.03x10^{-18} J

The number of photons is:

n=\frac{E1}{E}

where E1 is the energy of photon. Replacing:

n=\frac{0.5x10^{-3} }{1.03x10^{-18} }=4.8x10^{14}

Marrrta [24]3 years ago
4 0

Using the equation E = hc/λ we can find out how much energy a single photon of wavelength 193 nm has. E = Planck Constant * Speed of Light/193 nm

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A circular window of 30 cm diameter in a submarine can withstand a maximum force of 5.20 × 105 N. The maximum depth in a lake to
Svetach [21]

Answer: Option (b) is the correct answer.

Explanation:

The given data is as follows.

         F = 5.20 \times 10^{5} N

         g = 9.8 m/s

         radius = \frac{diameter}{2}

                    = \frac{30 cm}{2} = 15 cm = 0.15 m   (as 1 m = 100 cm)

Formula to calculate depth is as follows.

        F = \rho \times g \times h \times A

or,      h = \frac{F}{\rho \times g \times A}        

       h = \frac{5.2 \times 10^{5}}{1000 \times 9.8 \times (3.1416 \times (0.15 m^{2})}

           = 751 m

Thus, we can conclude that the maximum depth in a lake to which the submarine can go without damaging the window is closest 750 m.

3 0
3 years ago
Two coils close to each other have a mutual inductance of 32 mH. If the current in one coil decays according to I=I0e−αt, where
fiasKO [112]

The emf induced in the second coil is given by:

V = -M(di/dt)

V = emf, M = mutual indutance, di/dt = change of current in the first coil over time

The current in the first coil is given by:

i = i₀e^{-at}

i₀ = 5.0A, a = 2.0×10³s⁻¹

i = 5.0e^(-2.0×10³t)

Calculate di/dt by differentiating i with respect to t.

di/dt = -1.0×10⁴e^(-2.0×10³t)

Calculate a general formula for V. Givens:

M = 32×10⁻³H, di/dt = -1.0×10⁴e^(-2.0×10³t)

Plug in and solve for V:

V = -32×10⁻³(-1.0×10⁴e^(-2.0×10³t))

V = 320e^(-2.0×10³t)

We want to find the induced emf right after the current starts to decay. Plug in t = 0s:

V = 320e^(-2.0×10³(0))

V = 320e^0

V = 320 volts

We want to find the induced emf at t = 1.0×10⁻³s:

V = 320e^(-2.0×10³(1.0×10⁻³))

V = 43 volts

3 0
3 years ago
How far away is mars?
Elanso [62]

Answer:

about: 110.14 million mi

Explanation:

the distance to Mars from Earth is 140 million miles (225 million kilometers).But, distance to Mars from Earth is constantly changing.

Hope that was helpful.Thank you!!!

3 0
3 years ago
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A phosphodiester bond is used to:
bonufazy [111]

Answer:

A. Join glycerol to fatty acids

Explanation:

I majored in Physics.

4 0
2 years ago
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The radius of the planent venus is nearly the same as that of the earth,but its mass is only eighty percent that of the earth. I
oee [108]
Weight=mg
g=GM/r^2
g on venus is 0.80w as radius is kept constant
m of object is kept constant
w α g
w(venus( is 0.8w

7 0
3 years ago
Read 2 more answers
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