Answer:
8.5m/s
Explanation:
We are given that
Mass of object=m=0.50 kg
Initial velocity, u=0
Force=F=2.88 N
Time=1.48 s
a.We know that

Using the formula



Using the formula


Hence, the velocity of the object at the end of this time interval=8.5m/s
100/2.5 is 40.
40 is the energy that is being produced
The net force on the charge at the origin is -1.2×10-8
<u>Explanation:</u>
Solving the problem,
- Draw the x-axis and the locations of the given three charges.
- The forces applied on the charge at the origin and there are two of them, and since all the changes are positive, all the forces are repulsive.
- we have the formula, F = kq1Q/r².
- F1 = kq1Q/r²1 = (9.0*109Nm²/C²)(2.2*10^-9C)(3.5*10^-9C)/(1.5m)² = 31*10-9N = 3.1*10-8N. F1 points to the right (+x direction).
- F2 = kq2Q/r²2 = (9.0*109Nm²/C²)(5.4*10^-9C)(3.5*10^-9C)/(2.0m)² = 43*10^-9N = 4.3*10^-8N.
- F2 points to the left (-x direction).
- To find the net force we have to subtract the force F1 and force F2 .
- The net force is F(origin) = F1 - F2 = -1.2×10-8N.
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Anything that's dropped on or near the Earth accelerates at the rate of
9.8 m/s² on its way down. The mass of the object makes no difference.
After falling for 2 seconds, it's falling at the rate of 19.6 m/s.
Momentum = (mass) x (speed)
The egg's momentum is (5.07 kg) x (19.6 m/s) = 99.4 kg-m/s .
An air mass is a large pocket of air with a uniform temperature and humidity