If we know what we are reading, reaction time to the simple reaction task in this project will be less than reaction time to the voluntary action of your quadriceps, however, if we are reading for the first time, reaction time to the simple reaction task in this project will be more than reaction time to the voluntary action of your quadriceps.
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Explanation:</u></h3>
First, we need to know what is the reaction time. Reaction time is the amount of time it takes to respond to a stimulus. Now we will talk about voluntary and involuntary actions.
Voluntary action is an action that is thought of and consciously performed by the person. So we can say the person has full control over the situation. An involuntary action is one which occurs without the conscious choice of an organism. If the involuntary action occurred as a response to some stimulus it will be known as a reflex. If we compare the reaction time of voluntary action of our quadriceps and the simple reaction to the task given in the project, the reaction time could be less only if we have studied about the given question in the given task.
So the lines what we are reading will come to our mind involuntarily, but if we are talking about typing the answer the reaction time would be more as first, we have to form a structured sentence and then type it, so it will take more time.
Answer: A. True
Explanation: Combustion is a chemical process in which a substance reacts rapidly with oxygen and gives off heat. The original substance is called the fuel, and the source of oxygen is called the oxidizer. ... During combustion, new chemical substances are created from the fuel and the oxidizer.
Explanation:
The rate of reaction is the speed at which a chemical reaction takes place, defined as proportional to the increase in the concentration of a product per unit time and to the decrease in the concentration of a reactant per unit time. Reaction rates can vary dramatically.
Answer:
Option A:
Zn(s) + Cu^(2+) (aq) → Cu(s) + Zn^(2+)(aq)
Explanation:
The half reactions given are:
Zn(s) → Zn^(2+)(aq) + 2e^(-)
Cu^(2+) (aq) + 2e^(-) → Cu(s)
From the given half reactions, we can see that in the first one, Zn undergoes oxidation to produce Zn^(2+).
While in the second half reaction, Cu^(2+) is reduced to Cu.
Thus, for the overall reaction, we will add both half reactions to get;
Zn(s) + Cu^(2+) (aq) + 2e^(-) → Cu(s) + Zn^(2+)(aq) + 2e^(-)
2e^(-) will cancel out to give us;
Zn(s) + Cu^(2+) (aq) → Cu(s) + Zn^(2+)(aq)
