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2 years ago

HELP ME PLEASE SOMEONE!!

Mathematics

1 answer:

KiRa [710]2 years ago

8 0

You have the correct answer being (-5,3). Simply add the parentheses around the point

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The graph of the equation x^2+6x+y^2-16y=-9 is a circle. Choose True or False for each statement

BigorU [14]

Answer:

see the explanation

Step-by-step explanation:

we have

$x^2+6x+y^2-16y=-9$

Convert the equation of the circle in center radius form

Group terms that contain the same variable

$(x^2+6x)+(y^2-16y)=-9$

Complete the square twice. Remember to balance the equation by adding the same constants to each side

$(x^2+6x+9)+(y^2-16y+64)=-9+9+64$

$(x^2+6x+9)+(y^2-16y+64)=64$

Rewrite as perfect squares

$(x+3)^2+(y-8)^2=8^2$

The center of the circle is (-3,8)

The radius of the circle is 8 units

Verify each statement

A. The center of the circle is (3,-8).

False

The center of the circle is (-3,8)

B. The circle is tangent to the x-axis

True

The circle is tangent to x=5 and x=-11 and is tangent to y=0 and y=16

Remember that y=0 is the x-axis

C. The circle has a radius of 64

False

The radius of the circle is 8 units

7 0

3 years ago

Hazel McCurry offered $149,400 for a home that had been priced at $439,500. The seller agreed to the offer. If she made a $44,00

vredina [299]

149,400-44,000
=$105,400

8 0

3 years ago

Put in the simplest radical form

Nezavi [6.7K]

$(4 \sqrt[3]{4m^2})(5m \sqrt[3]{2m^2}) = 20m \sqrt[3]{8m^4} =20m.2m \sqrt[3]{m} =40m^2 \sqrt[3]{m}$

4 0

3 years ago

V(x)=x^2-25

Whitepunk [10]

Answer:

-∞ < x < -5 ∪ -5 < x < -3/2 ∪ -3/2 < x < ∞

Step-by-step explanation:

The domain of any polynomial is "all real numbers." The domain of any rational function excludes any values of the variable that result in the denominator being 0. The function is "undefined" there.

$v(x)=\dfrac{x^2-25}{2x^2+13x+15}=\dfrac{(x+5)(x-5)}{(x+5)(2x+3)}\qquad x\notin \{-5,-\dfrac{3}{2}\}$

The values x=-5 and x=-3/2 make the denominator of v(x) become 0, so those values are excluded from the domain of v(x). The function is "undefined" when its denominator is zero.

-∞ < x < -5 ∪ -5 < x < -3/2 ∪ -3/2 < x < ∞

_____

Additional comment

The numerator and denominator factors (x+5) cancel each other, so there is no vertical asymptote at x=-5. Rather, the function has a "hole" there, where it is undefined. The limit as the function approaches x=-5 from either direction is v(x) = 10/7.

7 0

2 years ago

Which equation has every number as a solution?

ikadub [295]

Answer:

the answer is D

Step-by-step explanation:

the equation works with every number placed where the x is, for example:

4(5+1)= 4×5 + 4

4×6=20+4

24=24

but it also works with

4(11+1)= 4×11 + 4

4×12=44+4

48=48

and it also works with every possible number you can think!

7 0

3 years ago

Read 2 more answers