Answer:
LibreOffice is an integrated suite of software applications used to perform office tasks such as word processing, presentation preparation and spreadsheet calculations
Answer:
sulfur dioxide
Explanation:
The scrubber is an apparatus installed in a coal-fired power plant to clean the passing gas through the smokestack. Due to the norm enacted through the clean air Act, almost all the scrubber used in the U.S is used to remove sulfur concentration from coal. it can remove approx 90-95% SO_2 from the smokestack.
Answer:
The answer is "583.042533 MPa".
Explanation:
Solve the following for the real state strain 1:

Solve the following for the real stress and pressure for the stable.
![K=\frac{\sigma_{r1}}{[\In \frac{I_{il}}{I_{01}}]^n}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5Csigma_%7Br1%7D%7D%7B%5B%5CIn%20%5Cfrac%7BI_%7Bil%7D%7D%7BI_%7B01%7D%7D%5D%5En%7D)
Solve the following for the true state stress and stress2.

![=\frac{\sigma_{r1}}{[\In \frac{I_{il}}{I_{01}}]^n} \times [\In \frac{I_{i2}}{I_{02}}]^n\\\\=\frac{399 \ MPa}{[In \frac{54.4}{47.7}]^{0.2}} \times [In \frac{57.8}{47.7}]^{0.2}\\\\ =\frac{399 \ MPa}{[ In (1.14046122)]^{0.2}} \times [In (1.21174004)]^{0.2}\\\\ =\frac{399 \ MPa}{[ In (1.02663509)]} \times [In 1.03915873]\\\\=\frac{399 \ MPa}{0.0114161042} \times 0.0166818905\\\\= 399 \ MPa \times 1.46125948\\\\=583.042533\ \ MPa](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%5Csigma_%7Br1%7D%7D%7B%5B%5CIn%20%5Cfrac%7BI_%7Bil%7D%7D%7BI_%7B01%7D%7D%5D%5En%7D%20%5Ctimes%20%5B%5CIn%20%5Cfrac%7BI_%7Bi2%7D%7D%7BI_%7B02%7D%7D%5D%5En%5C%5C%5C%5C%3D%5Cfrac%7B399%20%5C%20MPa%7D%7B%5BIn%20%5Cfrac%7B54.4%7D%7B47.7%7D%5D%5E%7B0.2%7D%7D%20%5Ctimes%20%5BIn%20%5Cfrac%7B57.8%7D%7B47.7%7D%5D%5E%7B0.2%7D%5C%5C%5C%5C%20%3D%5Cfrac%7B399%20%5C%20MPa%7D%7B%5B%20In%20%281.14046122%29%5D%5E%7B0.2%7D%7D%20%5Ctimes%20%5BIn%20%281.21174004%29%5D%5E%7B0.2%7D%5C%5C%5C%5C%20%3D%5Cfrac%7B399%20%5C%20MPa%7D%7B%5B%20In%20%281.02663509%29%5D%7D%20%5Ctimes%20%5BIn%201.03915873%5D%5C%5C%5C%5C%3D%5Cfrac%7B399%20%5C%20MPa%7D%7B0.0114161042%7D%20%5Ctimes%200.0166818905%5C%5C%5C%5C%3D%20399%20%5C%20MPa%20%5Ctimes%201.46125948%5C%5C%5C%5C%3D583.042533%5C%20%5C%20MPa)
Answer:
- hoop stress
- longitudinal stress
- material used
all this could led to the failure of the garden hose and the tear along the length
Explanation:
For the flow of water to occur in any equipment, water has to flow from a high pressure to a low pressure. considering the pipe, water is flowing at a constant pressure of 30 psi inside the pipe which is assumed to be higher than the allowable operating pressure of the pipe. but the greatest change in pressure will occur at the end of the hose because at that point the water is trying to leave the hose into the atmosphere, therefore the great change in pressure along the length of the hose closest to the end of the hose will cause a tear there. also the other factors that might lead to the failure of the garden hose includes :
hoop stress ( which acts along the circumference of the pipe):
αh =
EQUATION 1
and Longitudinal stress ( acting along the length of the pipe )
αl =
EQUATION 2
where p = water pressure inside the hose
d = diameter of hose, T = thickness of hose
we can as well attribute the failure of the hose to the material used in making the hose .
assume for a thin cylindrical pipe material used to be
≥ 20
insert this value into equation 1
αh =
= 60/2 = 30 psi
the allowable hoop stress was developed by the material which could have also led to the failure of the garden hose
Answer:
Explanation:
Given
Initial Thickness=45 mm
Final thickness=20 mm
Roll diameter=600 mm
Radius(R)=300 mm
coefficient of friction between rolls and strip (
)=0.15
maximum draft

Minimum no of passes
(b)draft per each pass

