3 years ago

What is the radius of a circle with a sector area of 7 (pi) sq ft. and an arc whose measure is 70°?

Mathematics

1 answer:

Digiron [165]3 years ago

7 0

The answer is 6ft hope its helps.Have a good day!

You might be interested in

Which can be used to find the distance between points at (-5,-12) and (-5,14)?

GREYUIT [131]

Pythagorean Theorem as follows: A^2+B^2=C^2

6 0

3 years ago

For this problem, I figured how the main question but I am not sure how to write an equation for it. Please help! I am not sure

inessss [21]

Answer:

y = 25x + 30

Step-by-step explanation:

hope it helps!

5 0

3 years ago

Read 2 more answers

I’ll mark brainlest:( i need help!

enyata [817]

Answer: Choice A) $3 \sqrt{26}$

==================================================

Work Shown:

$\text{The two points are } (x_1,y_1) = (6,7) \text{ and } (x_2,y_2) = (3,-8)\\\\d = \text{Distance between } (x_1,y_1) \text{ and } (x_2,y_2)\\\\d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2} = \text{Distance Formula}\\\\d = \sqrt{(6-3)^2+(7-(-8))^2}\\\\d = \sqrt{(6-3)^2+(7+8)^2}\\\\$

$d = \sqrt{(3)^2+(15)^2}\\\\d = \sqrt{9+225}\\\\d = \sqrt{234}\\\\d = \sqrt{9*26}\\\\d = \sqrt{9}*\sqrt{26}\\\\d = 3\sqrt{26}\\\\$

When going from 234 to 9*26, the idea here is to factor where one factor is the largest perfect square possible. That way we can use the rule $\sqrt{x*y} = \sqrt{x}*\sqrt{y}$ to break up the root and simplify.