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qaws [65]
2 years ago
6

7. How many moles of mercury(ii) oxide, hgo, are needed to produce 12. 5 g of oxygen, o2? 2 hgo(s) --->2 hg(l) o2(g)

Chemistry
1 answer:
svetoff [14.1K]2 years ago
5 0

Moles are the division of the mass and the molar mass. The moles of mercury (ii) oxide in the decomposition reaction needed to produce oxygen are 0.781 moles.

<h3>What is a decomposition reaction?</h3>

A decomposition reaction is a breakdown of the reactant into simpler products. The decomposition of mercury (ii) oxide can be shown as:

2HgO(s) → 2Hg(l) + O₂(g)

From the reaction, it can be said that 2 moles of mercury (ii) oxide decomposes to produce 1 mole of oxygen.

The moles of oxygen that needs to be produced are calculated as:

Moles = mass ÷ molar mass

= 12.5 gm ÷ 32 gm/mol

= 0.39 moles

0.39 moles of oxygen are needed to be produced.

From the stoichiometric coefficient of the reaction, the moles of HgO is calculated as: 2 × 0.39 = 0.781 moles

Therefore, 0.781 moles of HgO are required in the reaction.

Learn more about moles here:

brainly.com/question/3801333

#SPJ4

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The reaction C4H8(g)⟶2C2H4(g) C4H8(g)⟶2C2H4(g) has an activation energy of 262 kJ/mol.262 kJ/mol. At 600.0 K,600.0 K, the rate c
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According to the Arrhenius equation,

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where,

K_1 = rate constant at 600.0K = 6.1\times 10^{-8}s^{-1}

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T_2 = final temperature = 785.0K

Now put all the given values in this formula, we get:

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K_2=1.45\times 10^{-2}s^{-1}

Therefore, the rate constant at 785.0 K is, 1.45\times 10^{-2}s^{-1}

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