Answer:
In numerical order left to right, they are arranged by the number of protons in the nucleus of a single atom of each element
Answer:
The He₂ 2+ ion is more stable since it has a higher bond order (bond order = 1) than the He₂ + ion (bond order = 1/2).
Explanation:
Molecular orbital of He₂⁺
There are two electrons in bonding and 1 electron in antibonding orbital
Bond order = 
= 
Molecular orbital of He₂⁺²
There are two electrons in bonding and 0 electron in antibonding orbital
Bond order = 
= 1
So bond order of He₂⁺² is 1 which is more stable than He₂⁺ whose bond order is .
The chemical formula of Iron (III) Sulfide is FeSO3. This element or compound has another name which is <span>ferric sulfide or sesquisulfide.</span>
Answer:
[Cl2O5] = 1.60 M
Explanation:
- 2Cl2O5(g) → 2Cl2(g) + 5O2(g)
at T ⇒ r = (17.4/M.s)*[Cl2O5]²
1) [Cl2O5] = 1.46 M
⇒ t = 0.400 s ⇒ [Cl2O5] = ?
rate law gnral:
- - ra = K(Ca)∧α = - δCa/δt
∴ K = 17.4 /M.s
∴ α = 2
⇒ - ∫δCa/Ca² = K∫δt
⇒ [ 1/Ca - 1/Cao ] = K*t
⇒ 1/Ca = K*t + 1/Cao
⇒ Ca = 1/K*t + Cao = [Cl2O5]
∴ Cao = 1.46 M
∴ t = 0.400 s
⇒ [Cl2O5] = 1/[(17.4/M.s)*(0.400s)] + 1.46 M
⇒ [Cl2O5] = 0.1436 M + 1.46 M
⇒ [Cl2O5] = 1.604 M
Answer:
Radicals
Explanation:
A radical refers to a chemical specie that contains unpaired electrons in their dot electron diagrams.
Radicals contain an odd number of electrons. They are commonly called odd electron species.
Radicals participate in a number of important reactions. A typical example is the halogenation of alkanes in the presence of light.
Examples of radicals include; Br. , Cl. , F. etc
