1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
o-na [289]
2 years ago
15

What is the pH of a solution with (H+) =2.3x10 -6

Chemistry
1 answer:
castortr0y [4]2 years ago
5 0
P
H
=
−
log
10
[
H
3
O
+
]
=
−
log
10
{
2.3
×
10
−
6
}
=
−
{
−
5.64
}
=
5.64
You might be interested in
The orbital radius of Venus is 0.72 AU. What is this distance in kilometers? (One AU is about 150 million kilometers.)
Evgen [1.6K]
<span>The answer is D) 108 million kilometers. To solve this problem, you must perform a simple unit conversion calculation. 1 AU = 150,000,000 km is the conversion factor. Take the radius of Venus, .72 AU, and multiply it by 150,000,000 km/1 AU. You flip the conversion factor so that the units of the original distance in the numerator cancel the units in the denominator of the conversion factor. completing the calculation gives you 108,000,000 km</span>
6 0
3 years ago
What is a good essential question for the subject molecular compounds
Mashutka [201]
Why do molecules combined into chains?
6 0
3 years ago
The mole fraction of iodine, i2, dissolved in dichloromethane, ch2cl2, is 0.115. what is the molal concentration, m, of iodine i
german
The molality of a solute is equal to the moles of solute per kg of solvent. We are given the mole fraction of I₂ in CH₂Cl₂ is <em>X</em> = 0.115. If we can an arbitrary sample of 1 mole of solution, we will have:

0.115 mol I₂

1 - 0.115 = 0.885 mol CH₂Cl₂

We need moles of solute, which we have, and must convert our moles of solvent to kg:

0.885 mol x 84.93 g/mol = 75.2 g CH₂Cl₂ x 1 kg/1000g = 0.0752 kg CH₂Cl₂

We can now calculate the molality:

m = 0.115 mol I₂/0.0752 kg CH₂Cl₂
m = 1.53 mol I₂/kg CH₂Cl₂

The molality of the iodine solution is 1.53.
5 0
3 years ago
Why do you think steeples and roofs might appear green, but a copper square does not?
Masteriza [31]
Because the copper roofs, have been outside for a while and oxidization has occurred.
When metals become oxidized they rust, but when copper becomes oxidized, it turns greenish.
So copper roofs oxidize and turn green from being outside and a copper square doesn’t if it’s inside.
8 0
2 years ago
Gold has a density of 1,200 lb./ft. What is the density of gold in g/em? For conversion factors use I lb. 453.6 g, and l inch-2.
Jlenok [28]

<u>Answer:</u> The density of gold in g/cm^3 is 19.22g/cm^3

<u>Explanation:</u>

Density is defined as the ratio of mass of the object and volume of the object. Mathematically,

\text{Density}=\frac{\text{Mass of the object}}{\text{Volume of the object}}

We are given:

Density of gold = 1200lb/ft^3

Using conversion factors:

1 lb = 453.6 g

1 feet = 12 inches

1 inch = 2.54 cm

Converting given quantity into g/cm^3, we get:

\Rightarrow (\frac{1200lb}{ft^3})\times (\frac{453.6g}{1lb})\times (\frac{1ft}{12inch})^3\times (\frac{1inch}{2.54cm})^3\\\\\Rightarrow 19.22g/cm^3

Hence, the density of gold in g/cm^3 is 19.22g/cm^3

6 0
3 years ago
Other questions:
  • The reaction ch4 (g) + 2 o2 (g) ? co2 (g) + 2 h2o (g) is: the reaction ch4 (g) + 2 o2 (g) co2 (g) + 2 h2o (g) is: an exothermic
    10·1 answer
  • What are metallic bonds?
    15·1 answer
  • What is the number of electrons in the outermost energy level of an oxygen atom
    15·2 answers
  • Which soil layer is the least similar to the underlying rock
    10·2 answers
  • Joe the scientist wants to figure out the angle for throwing a football that
    15·2 answers
  • Which of the following elements would have the greatest attraction for
    10·1 answer
  • Helppppp meeeeeeeeeeeeeeeeeeeeeeeeeeeee ill mark brainlist
    7·2 answers
  • Metallic Bond<br> When nitrogen shares electrons with oxygen, what kind of bond is made?
    5·1 answer
  • How did the forensic sculptor/.facial reconstructionist assist in this case? <br><br><br> FORENSIC
    12·1 answer
  • Compounds of boron and hydrogen are remarkable for their unusual bonding (described in Section 14.5) and also for their reactivi
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!