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Oxana [17]
3 years ago
10

PLEASE HELP ME ITS DUE IN 25 MINUTES True or false iron and nickel are less dense than silicates ?

Chemistry
2 answers:
Pani-rosa [81]3 years ago
6 0
False, iron and nickel is apart of the core in the earth. meaning it’s more dense that silicates.
just olya [345]3 years ago
5 0
The answer is false
Iron and nickel is more dense
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Vesna [10]

Covalent bonds are formed when 2 neutral atoms come together to share a pair of electrons, where each atom contributes one electron each to be shared.

The covalent bond is kept together by the electrostatic attraction between the nuclei of the atoms and the shared pair of electrons.

Covalent bonds are usually formed between non metals with a small difference in their electro negativity.

the correct answer is

A. Neutral atoms coming together to share electrons

7 0
4 years ago
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an engineering team is conducting a trial launch of a few rocket . which part is the engineering process is the team in ?
brilliants [131]

Answer:

Evaluate the result (Apex)

Explanation:

7 0
3 years ago
What is the Kb expression for aniline (C6H5NH2)?
Dimas [21]
This is what i got The KB expression for aniline c6h5nh2 is: For C6H5NH2 + H2O >< C6H5NH3+ <span>OH-Kb = 4.3 x (10 ^ -10) = [C6H5NH3+][OH-] / [C6H5NH2]

hope this helps:)

</span>
4 0
4 years ago
Read 2 more answers
A gas mixture with 4 mol of Ar, x moles of Ne, and y moles
maks197457 [2]

Answer:

a) \Delta G_{mixing}=\frac{R*T}{12}*[4*ln (1/3) +x*ln (x/12) +(8-x)*ln ((8-x)/12)]

b) x=4

c) \Delta G_{max}=-2721.9 J/mol

Explanation:

Gas mixture:

n_{Ar}= 4 mol

n_{Ne}= x mol

n_{Xe}= y mol

n_{tot}= n_{Ar} + n_{Ne} + n_{Xe}=3*n_{Ar}

n_{Ne} + n_{Xe}=2*n_{Ar}

x + y=8 mol

y=8 mol- x

Mol fractions:

x_{Ar}=\frac{4 mol}{12 mol}=1/3

x_{Ne}=\frac{x mol}{12 mol}=x/12

x_{Xe}=\frac{8 - x mol}{12 mol}=(8-x)/12

Expression of \Delta G_{mixing}

\Delta G_{mixing}=R*T*\sum_{i]*x_i*ln (x_i)

\Delta G_{mixing}=R*T*[1/3*ln (1/3) +x/12*ln (x/12) +(8-x)/12*ln ((8-x)/12)]

\Delta G_{mixing}=\frac{R*T}{12}*[4*ln (1/3) +x*ln (x/12) +(8-x)*ln ((8-x)/12)]

Expression of \Delta G_{max}

\frac{d \Delta G_{mixing}}{dx}=0

\frac{d \Delta G_{mixing}}{dx}=\frac{R*T}{12}*[ln (x/12)+12-ln ((8-x)/12)-12]

0=\frac{R*T}{12}*[ln (x/12)-ln ((8-x)/12)

0=[ln (x/12)-ln ((8-x)/12)

ln (x/12)=ln ((8-x)/12)

x=(8-x)

x=4

\Delta G_{max}=\frac{8.314*298}{12}*[4*ln (1/3) +4*ln (4/12) +(8-4)*ln ((8-4)/12)]

\Delta G_{max}=\frac{8.314*298}{12}*[4*ln (1/3) +4*ln (1/3) +(4)*ln (1/3)]

\Delta G_{max}=\frac{8.314*298}{12}*[12*ln (1/3)]

\Delta G_{max}=-2721.9 J/mol

4 0
3 years ago
A red blood cell is placed into each of the following solutions. Indicate whether crenation, hemolysis, or neither will occur. S
Burka [1]

Answer:

Solution A: crenation

Solution B: hemolysis

Solution C: hemolysis

Solution D: crenation

Solution E: crenation

Explanation:

Hemolysis is the rupturing of red blood cells, which results in the release of hemoglobin (from within the red blood cells) into the plasma. If a red blood cell is placed in a hypotonic solution, water will flow into the cell, the cell will swell and hemolysis will.

Crenation: when a red blood cell is placed in a <em>hypertonic solution (</em>such as highly saline solution), the red blood cell will lose water(osmosis) and will shrink in size. The red blood cell has undergone crenation.

In order for a red blood cell to prevent from undergoing hemolysis or crenation, the cell must be placed in an<em> isotonic solution, </em>i.e either in <u>0.9% (m/v) NaCl solution</u> or <u>5% glucose solution</u>

  • Solution B and Solution C are hypotonic solution, thus red blood cell has undergone hemolysis.
  • Solution A, D and E are hypertonic solution. thus red blood cell has undergone crenation
8 0
3 years ago
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