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Nikitich [7]
2 years ago
9

True or False? Some solids after mixing with other solids can be distinguished from each other

Chemistry
2 answers:
N76 [4]2 years ago
8 0
True, it all depends on the sizes
katen-ka-za [31]2 years ago
4 0

Answer:

True

Explanation:

Depends of the size and comparison

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How many neutrons are probably in the nucleus of an element of atomic weight 197? 
Ratling [72]
Atomic weight = 197
symbol = Au
electrons = 79

neutrons = 197 - 79 = 118

<u>answer: E</u>
4 0
3 years ago
How much volume in mL of 0.65 M HCI solution can be made by diluting 150 mL of 9.75 M HCI
Fynjy0 [20]
150 x 9.75/ 0.65 = L
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3 years ago
Which property can be attributed to an ideal gas?
DENIUS [597]
B The collisions of the particles are elastic
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2 years ago
According to the experimental procedure of Experiment F1, 135 microliters of acetophenone (120.15 g/mol, 1.03 g/mL) was reacted
Delicious77 [7]

Answer: The theoretical yield of 4-nitrochalcone is, 2.13\times 10^2

Explanation : Given,

Volume of acetophenone = 135  microliters = 135 × 10⁻⁶ L = 0.135 mL

conversion used : (1 microliter = 10⁻⁶ L) and (1 L = 1000 mL)

Density of acetophenone = 1.03 g/mL

Mass of acetophenone = Density × Volume = 1.03 g/mL × 0.135 mL = 0.139 g

Mass of 4-nitrobenzaldehyde = 127 mg  = 0.127 g

Conversion used : (1 mg = 0.001 g)

First we have to calculate the moles of acetophenone and 4-nitrobenzaldehyde

\text{Moles of acetophenone}=\frac{\text{Given mass acetophenone}}{\text{Molar mass acetophenone}}

\text{Moles of acetophenone}=\frac{0.139g}{120.15g/mol}=0.00116mol

and,

\text{Moles of 4-nitrobenzaldehyde}=\frac{\text{Given mass 4-nitrobenzaldehyde}}{\text{Molar mass 4-nitrobenzaldehyde}}

\text{Moles of 4-nitrobenzaldehyde}=\frac{0.127g}{151.12g/mol}=0.000840mol

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

C_8H_8O+C_7H_5NO_3\rightarrow C_{15}H_{11}NO_3

From the balanced reaction we conclude that

As, 1 mole of 4-nitrobenzaldehyde react with 1 mole of acetophenone

So, 0.000840 mole of 4-nitrobenzaldehyde react with 0.000840 mole of acetophenone

From this we conclude that, acetophenone is an excess reagent because the given moles are greater than the required moles and 4-nitrobenzaldehyde is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of 4-nitrochalcone

From the reaction, we conclude that

As, 1 mole of 4-nitrobenzaldehyde react to give 1 mole of 4-nitrochalcone

So, 0.000840 mole of 4-nitrobenzaldehyde react to give 0.000840 mole of 4-nitrochalcone

Now we have to calculate the mass of 4-nitrochalcone

\text{ Mass of 4-nitrochalcone}=\text{ Moles of 4-nitrochalcone}\times \text{ Molar mass of 4-nitrochalcone}

Molar mass of 4-nitrochalcone = 253.25 g/mole

\text{ Mass of 4-nitrochalcone}=(0.000840moles)\times (253.25g/mole)=0.21273g=212.73mg=2.13\times 10^2mg

(1 g = 1000 g)

Therefore, the theoretical yield of 4-nitrochalcone is, 2.13\times 10^2mg

4 0
3 years ago
Why you share some characteristics with your mother and some with your father.
Genrish500 [490]

Answer:

Half of your fathers DNA and half of your mothers DNA are combined in you, so you will inherit some of their traits.

6 0
2 years ago
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