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2 years ago

Solve the following:-

Mathematics

1 answer:

Mazyrski [523]2 years ago

5 0

Step-by-step explanation:

I solved it now, you can check by the pic attached to the answer.

thank you very much. ;-) ♥ ♥

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Students are asked to memorize a list of 100 words. The students are given periodic quizzes to see how many words they have memo

Yuri [45]

Answer:

C. dL/dt=k(100−L)

Step-by-step explanation:

The rate of change of the number of words memorized is proportional to the number of words left to be memorized.

The rate of change is dL/dt.

The rate is a constant k. Since the rate is proportional to the number of words left to be memorized, and the initial number of words is 100, k has to be multiplied by (100-L).

So the correct answer is:

C. dL/dt=k(100−L)

6 0

3 years ago

Emily is entering a bicycle race for charity. Her mother pledges $0.30 for every 0.25 mile she bikes. If Emily bikes 8 miles, ho

spayn [35]

I believe ur answer is 9.60

3 0

3 years ago

2. angle ABE = angle MNP <br><br> Write another valid congruency statement:

Free_Kalibri [48]

Given:

$\Delta ABE\cong \Delta MNP$

To find:

The congruent angles and sides, then find the another valid congruency statement.

Solution:

We have,

$\Delta ABE\cong \Delta MNP$

We know that, corresponding parts of congruent triangles are congruent (CPCTC).

Using CPCTC, we get

Angles:

$\angle A\cong \angle M$

$\angle B\cong \angle N$

$\angle E\cong \angle P$

Sides:

$AB\cong MN$

$BE\cong NP$

$AE\cong MP$

The another congruent statement is $\Delta BEA\cong \Delta NPM$ .

Therefore, the required table is

Angles Sides

$\angle A\cong \angle M$ $AB\cong MN$

$\angle B\cong \angle N$ $BE\cong NP$

$\angle E\cong \angle P$ $AE\cong MP$

The another congruent statement is $\Delta BEA\cong \Delta NPM$ .

4 0

3 years ago

A line has slope -1. It passes through the point Q(2, -n) and R(4, -3). What is the value of n?

dsp73

Answer:

i need this answer too

Step-by-step explanation:

lol

7 0

3 years ago

Chad and Victoria are playing a game with a quarter and a spinner divided into sixths numbered one through six each player spins

rodikova [14]

The simple way to do this is to multiply the number of outcomes of one object times the number of outcomes in the other object. In this case a quarter has 2 sides, heads and tails. Since the spinner has 6 sections, there are 6 outcomes.

With this we can do, 2x6=12.

Therefore there are 12 outcomes

8 0

3 years ago