Answer:
solution
we know that .
s=ut+½at²
now, putting the values in the second equation of motion ,
we get,
S=20×10+1/2×(10)²
S=200+1×100
S=200+100
S=300m
the distance covered by given body or object in 10 seconds is 300 m.
The given question is incomplete. The complete question is as follows.
Measurements show that the enthalpy of a mixture of gaseous reactants decreases by 338 kJ during a certain chemical reaction, which is carried out at a constant pressure. Furthermore, by carefully monitoring the volume change it is determined that 187 kJ of work is done on the mixture during the reaction. Calculate the change in energy of the gas mixture during the reaction. Be sure your answer has the correct number of significant digits. Is the reaction exothermic or endothermic ?
Explanation:
The given data is as follows.
Change in enthalpy (
) = -338 kJ (as it is a decrease)
Work done = 187 kJ,
Change in energy (
) = ?
Now, according to the first law of thermodynamics the formula is as follows.

Hence, putting the given values into the above formula as follows.

Also, we know that W = 
so,

= -151 kJ
Thus, we can conclude that the change in energy of the gas mixture during the reaction is -151 kJ.
A solution is a value or a collection of values.. when substituted for the unknowns, the equation become an equality.
Example : x + 2 = 7
When we out the 5 in place of x we get: 5 + 2 = 2
Explanation:
It is given that,
The acceleration of a particle,
(negative as the particle is decelerating)
Initial distance, x₁ = 20 m
Initial time, t₁ = 4 s
New distance x₂ = 4 m
Velocity, v = 10 m/s
(A) Calculating initial distance using second equation of motion as :


u = 21 m/s
When velocity of the particle is zero, time taken is t (say). Using first equation of motion as :


t = 2.62 seconds
So, the velocity of the particle is zero at t = 2.62 seconds.
(B) Velocity at t = 11 s

v = 13 m/s
Total distance covered at t = 11 s. The overall path travelled by the particle during its entire journey is called total distance covered.


d = 132.48 m
So, the distance travelled by the particle at t = 11 seconds is 132.48 meters.
Answer: Judging by your job 24 hours you will get paid money for each hour
Explanation: