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Ganezh [65]
3 years ago
13

True or false The sound of a police siren would be an example of the Doppler effect

Physics
1 answer:
Stella [2.4K]3 years ago
3 0
The answer to the question is True.
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If a football player does 39000 J of work, how much power does the football player exert in 5 minutes
Drupady [299]

Answer:

Power = 130 watt

Explanation:

Power is described as the ability to do work, it is also defined as the amount of work in Joules done in a given time in seconds. Mathematically, it is represented as:

power = \frac{work (J)}{Time (s)}

In this example, power is calculated as follows:

Work = 39000 J

Time = 5 minutes

converting the time from minutes to seconds:

1 minute = 60 seconds

∴ 5 minutes = 60 × 5 = 300 seconds

\therefore power = \frac{39000}{300} \\power = 130 watt

N:B the unit for power can also be represented as Joules/seconds or J/s or JS⁻¹

6 0
3 years ago
Do any individual air molecules travel the length of the tube? how do you know?
Ivanshal [37]

When a gas is inside the tube, the individual air molecules travel the length of the tube.

<h3>What is molecules?</h3>

The individual particle of a gas element moving randomly inside the element structure.

When the gas contained in a container, the molecules move randomly inside it. According to the kinetic theory of gases, molecules travel the mean distance. The air molecules vibrates horizontally parallel to the length of the tube.

In an open tube, air molecules are distant from each other. So, they can travel the length of the tube.

Thus, individual air molecules travel the length of the tube.

Learn more about molecules.

brainly.com/question/19922822

#SPJ4

7 0
2 years ago
A 4 kg book and a 7 kg lamp are both in the living room. If the force of gravity between them is 2.99x10^-10 N. How far apart ar
Xelga [282]

Force of gravity = 'G' (mass₁)(mass₂) / (distance)²

'G' is the gravitational constant for SI units =  6.67 x10⁻¹¹ newton-meter²/kg²

You said that the force is          <u>2.99 x 10⁻¹⁰</u> = (6.67x10⁻¹¹) (4) (7) / D²

Multiply each side by D² :    2.99 x 10⁻¹⁰ D²  =  (6.67x10⁻¹¹) (28)

Divide each side by  2.99 x 10⁻¹⁰  :          D² = (28) (6.67 x10⁻¹¹) / (2.99 x 10⁻¹⁰)

Take the square root of each side:      D = square root of all that

Stuff it through my calculator:

                               D = square root of  [  (28) (6.67 x10⁻¹¹) / (2.99 x 10⁻¹⁰)  ] =

                                  √ ( 6.2462...) meters²  = 

                                        <em>2.5 meters </em> (rounded)

===================

To get the feel:

-- The book weighs about    8.8  pounds  (big book)
-- The lamp weighs about  15.4  pounds
-- They're about 8.2 feet apart.
-- The strength of the gravitational force
           between them is about                  0.000 000 001 075 of an ounce .

5 0
2 years ago
At a certain instant, the charge stored by a capacitor in an LC circuit is 60 C and the energy stored by the capacitor is nine
rusak2 [61]

Complete Question: At a certain instant, the charge stored by a capacitor in an LC circuit is 60 microC and the energy stored by the capacitor is nine sixteenths of its maximum value. If the circuit's frequency of oscillation is (40 /pi) Hz, what is the maximum current in the circuit?

Answer:

Imax = 6.4 mA

Explanation:

In a oscillating LC circuit, energy is exchanged all time between the capacitor and the inductor, in such a way that any time, the total energy in the circuit is equal to the sum of  the energies stored in both circuit elements.

When the capacitor is fully discharged, the energy is stored only at the inductor, so the current is maximum.

We can write the following equation in this case:

1/2 L*Imax² = 1/2 Li² + 1/2q₀²/C

We have as givens, q₀= 60μC and  f=40/π Hz.

We also know, that when the capacitor is charged with this q₀, the energy stored in it (actually in the electric  field between plates) is 9/16 of its maximum value, which must be equal to the maximum energy stored in the inductor (due to the energy conservation), so, we can write the following equation:

1/2 q₀²/C = 9/16*1/2*L*Imax²

In a pure oscillating circuit, there is a fixed relationship between f, L and C, as follows:

ω₀² = 1/LC ⇒ LC = 1/ω₀²

Simplifying common terms, and manipulating terms, we have:

I²max =16*q₀²*(2*π*f₀)² = 16* (60)²*4*π²*((40)/π)² / 9

⇒ I²max = 16*(60)²*(40)²*4*10⁻¹²/9 A

⇒ I max = ((8*60*40) / 3) * 10⁻⁶ A = 6.4*10⁻³ A = 6.4 mA

3 0
3 years ago
Which of these describes the object’s motion after the time shown on the graph?
DanielleElmas [232]
There's nothing popping up
7 0
3 years ago
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