Answer is: the percent purity of the sodium bicarbonate is 56.83 %.
1. Chemical reaction: 2NaHCO₃ + H₂SO₄ → 2CO₂ + 2H₂O + Na₂SO₄.
2. m(NaHCO₃) = 3.50 g
n(NaHCO₃) = m(NaHCO₃) ÷ M(NaHCO₃).
n(NaHCO₃) = 3.50 g ÷ 84 g/mol.
n(NaHCO₃) = 0.042 mol.
3. From chemical reaction: n(NaHCO₃) : n(CO₂) = 1 : 1.
n(CO₂) = 0.042 mol.
m(CO₂) = 0.042 mol · 44 g/mol.
m(CO₂) = 1.83 g.
4. the percent purity = 1.04 g/1.83 g ·100%.
the percent purity = 56.8 %.
the same
Explanation:
Within the nucleus of individual atoms of the same element, the proton number is the same.
All atoms of the same kind from the same element have the same number of protons.
The number of protons does not change, it remains fixed after a chemical reaction.
Different elements have different number of protons that typifies and makes them unique.
But atoms of the same element have the same number of protons in them.
learn more;
Atomic number brainly.com/question/5425825
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0.428571429 moles is your exact answer. Hope this helps!!! (:
That is correct c
Explanation
