Question is incomplete, complete question is;
A 34.8 mL solution of 
(aq) of an unknown concentration was titrated with 0.15 M of NaOH(aq).
If it takes 20.4 mL of NaOH(aq) to reach the equivalence point of the titration, what is the molarity of 
? For your answer, only type in the numerical value with two significant figures. Do NOT include the unit.
Answer:
0.044 M is the molarity of (aq).
Explanation:
The reaction taking place here is in between acid and base which means that it is a neutralization reaction .
To calculate the concentration of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is
are the n-factor, molarity and volume of base which is NaOH.
We are given:
Putting values in above equation, we get:
0.044 M is the molarity of (aq).
Answer:
Explanation:
A substance melting is a physical change and the properties of the substance will remain same, only that the substance will just become liquid.
On the other hand, burning is a chemical change which produces an entirely new compount(in most cases, ash) which does not have the same properties as the original object
<h3>
Answer:</h3>
2.83 g/cm³
<h3>
Explanation:</h3>
- Density of a substance is the ratio of mass of the substance to its volume.
Therefore;
- Density is given by dividing mass of a substance by its volume.
- It is measure in g/cubic centimeters or kg per cubic meters.
In this case;
Density of Al = 2830 Kg/m³
We are required to convert is to g/cm³
We use the relationship;
1 g/cm³ = 1000 kg/m³
Therefore;
= 2830 kg/m³ ÷ 1000 kg/m³
= 2.83 g/cm³
Hence, 2830 kg/m³ of Aluminium is equivalent to 2.83 g/cm³
Hey there!:
Molar mass Ca(NO2)2 = 132.089 g/mol
Mass of solute = 120 g
Number of moles:
n = mass of solute / molar mass
n = 120 / 132.089
n = 0.0009084 moles of Ca(NO2)2
Volume in liters of solution :
240 mL / 1000 => 0.24 L
Therefore:
Molarity = number of moles / volume of solution
Molarity = 0.0009084 / 0.24
Molarity = 0.003785 M
Hope that helps!
Answer:
K=1.93
Explanation:
Given reactions are:
A +2B ⇄ 2C K1=2.79
2C ⇄ D K2=0.186
D⇄ A+ 2B K=?
If we reverse the reaction then the euillibrium constant also become reciprocal of original value:
3rd reaction is a combination of reciprocal of 1st and 2nd reaction
2C⇄A +2B 1/K1;........................1
D ⇄ 2C 1/K2; ..............................2
On adding 1 and 2
D ⇄A +2B 
K=1.93
