Question

Determine the Ka for CH3NH3+ at 25*C. The Kb for CH3NH2 is 4.4 x 10-4.

Answer 1

Answer:

Ka= 2.3 x 10^-11

Explanation:

so Ka x Kb = Kw where Kw=10^-14 at 25 degrees Celsius

plugging in Kb and Kw, we have

Ka x 4.4 x 10^-4 = 10^-14

solving for Ka,

Ka= (10^-14)/(4.4 x 10^-4)

Ka= 2.3 x 10^-11