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Anon25 [30]
3 years ago
10

Which pair of atoms will form an ionic compound? A) One atom of oxygen and two atoms of fluorine Eliminate B) One atom of calciu

m and two atoms of chlorine C) One atom of nitrogen and three atoms of fluorine D) Two atoms of nitrogen and four atoms of oxygen
Chemistry
2 answers:
wlad13 [49]3 years ago
4 0
An ionic compound is made up of a metal and a nonmetal. This eliminates answer choice A, C, and D because both of the elements listed are nonmetal.

Your correct answer is B) One atom of calcium and two atoms of chlorine. This is because calcium is a metal, and chlorine is a nonmetal.
suter [353]3 years ago
4 0

Answer : The correct option is, (B) One atom of calcium and two atoms of chlorine.

Explanation :

Ionic compound : It is a compound in which the atoms are bonded through the ionic bond.  The ionic bonds are formed between the one metal and one non-metal. It is formed by the complete transfer of electrons.

Covalent compound : It is a compound in which the atoms are covalently bonded. The covalent bonds are formed between two non-metals.  The covalent bonds are formed by the equal sharing of the electrons.

From the given options, only option (B) pair of atoms will form an ionic compound because calcium is a metal and chlorine is a non-metal. While the other options will not form an ionic compound because the two atoms are non-metals.

Hence, the correct option is, (B) One atom of calcium and two atoms of chlorine.

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Iron has density 7.87 g/cm^3. if 52.4 g of iron is added to 75.0 mL of water in a graduated cylinder, to what volume reading wil
vlada-n [284]

Answer:

6.66 mL

Explanation:

The increase in the volume is due to the addition of the iron whose volume can be calculated as:

Using,

Density = Mass / Volume

Given that:

Density of Iron = 7.87 g/cm³

Mass of iron = 52.4 g

Thus, volume is:

Volume = Mass / Density = 52.4 / 7.87 cm³ = 6.66 cm³

Also, 1 cm³ = 1 mL

<u>The rise in the volume = 6.66 mL</u>

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The density of potassium, which has the BCC structure, is 0.855 g/cm3. The atomic weight of potassium is 39.09 g/mol. Calculate
Nimfa-mama [501]

Answer:

lattice parameter = 5.3355x10^-8 cm

atomic radius = 2.3103x10^-8 cm

Explanation:

known data:

p=0.855 g/cm^3

atomic mass = 39.09 g/mol

atoms/cell = 2 atoms

Avogadro number = 6.02x10^23 atom/mol

a) the lattice parameter:

Since potassium has a cubic structure, its volume is equal to:

v = [(atoms/cell)x(atomic mass)/(p)x(Avogadro number)]

substituting values:

v =[(2)x(39.09)/(0.855x6.02x10^23)]=1.5189x10^-22 cm^3

but as the cell volume is

a^3 =v

a=\sqrt[3]{v}=\sqrt[3]{1.5189x10^{-22} } = 5.3355x10^-8 cm

for a BCC structure, the atomic radius is equal to

r=\frac{ax\sqrt{3} }{4}=\frac{5.3355x10^{-8}x\sqrt{3}  }{4}=2.3103x10^{-8}cm

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