PLEASE help me with this math problem!! Will give brainliest!! :)
1 answer:
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<h2><u>Given</u><u> </u><u>:</u><u>-</u></h2>
length of rectangle = ( 4n-5 )
breadth of rectangle = ( 3n-2)
<h2><u>To</u><u> </u><u>find</u><u> </u><u>:</u><u>-</u></h2>Area and perimeter of rectangle.
<h2><u>solution</u><u> </u><u>:</u><u>-</u></h2>by the question ,
We know the area of rectangle = length × breadth
Area = (4n -5) (3n-2)
now ,
perimeter = 2 ( length + breadth (
= 2 ( 4n-5 + 3n-2)
= 2 ( 7n-7)
= 14n -14
<u>I</u><u> </u><u>hopes</u><u> </u><u>this</u><u> </u><u>helps</u><u>.</u>
Add 3y to both sides
10x = -150 +3y
subtract -150 from both both sides
10x + 150 = 3y
then divide both sides by 3 (and going to switch the two sides cuz i prefer it that way)
y = (10/3)x + 50
so for graphing you take the y intercept
which is 50 and put a point there
slope (10/3) is rise/over run
so going down and to the left from your y intercept (cuz the slope is positive) count 10 then go over 3
put a point
do it again
then for the other way go up 10 and over 3
that’s graphing
i’ll graph it too but it’ll be sloppy so i figured i’d explain it too
10x = -150 +3y
subtract -150 from both both sides
10x + 150 = 3y
then divide both sides by 3 (and going to switch the two sides cuz i prefer it that way)
y = (10/3)x + 50
so for graphing you take the y intercept
which is 50 and put a point there
slope (10/3) is rise/over run
so going down and to the left from your y intercept (cuz the slope is positive) count 10 then go over 3
put a point
do it again
then for the other way go up 10 and over 3
that’s graphing
i’ll graph it too but it’ll be sloppy so i figured i’d explain it too