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Lynna [10]
2 years ago
11

For the neutralization reaction involving hno3 and ca(oh)2, how many liters of 1. 55 m hno3 are needed to react with 45. 8 ml of

a 4. 66 m ca(oh)2 solution?
Chemistry
1 answer:
Agata [3.3K]2 years ago
6 0

For the neutralization reaction involving HNO₃ and Ca(OH)₂, liters of 1.55 M HNO₃ are needed to react with 45.8 ml of a 4.66 m Ca(OH)₂ solution is 0.270 L.

<h3>What is neutralization reaction?</h3>

Those reactions in which acids and bases will combine with each other for the formation of water molecule and salt, is known as neutralization reaction.

Given chemical reaction is:

2HNO₃ + Ca(OH)₂ → 2H₂O + Ca(NO₃)₂

Moles (n) of Ca(OH)₂ will be calculated by using the below formula:
M = n/V, where

M = molarity = 4.66M

V = volume = 45.8 mL = 0.045 L

n = (4.66)(0.045) = 0.2097 mol

From the stoichiometry of the reaction,

1 mole of Ca(OH)₂ = reacts with 2 moles of HNO₃

0.2097 mole of Ca(OH)₂ = reacts with 2×0.2097=0.419 moles of HNO₃

Again by using the molarity equation volume will be calculated for HNO₃ as:

V = (0.419) / (1.55) = 0.270 L

Hence required volume of HNO₃ is 0.270 L.

To know more about neutralization reaction, visit the below link:

brainly.com/question/23008798

#SPJ4

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Why is enthalpy important?
belka [17]
The Law of Conservation of Energy states that, within a closed system, the total amount of energy remains constant. However, energy may change from kinetic to potential and vice versa. The total energy will not have changed. <span>Enthalpy is a measure of the amount of energy that exists in a system at constant pressure. </span>
7 0
2 years ago
a culinary student fills a 40ml container with 37.2 grams of vegetable oil.What is the density of the oil
Lynna [10]

Answer:

<h2>0.93 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 37.2 g

volume = 40 mL

We have

density =  \frac{37.2}{40}  \\  = 0.93

We have the final answer as

<h3>0.93 g/mL</h3>

Hope this helps you

4 0
2 years ago
How much mass of sodium chloride ( ) should be dissolved in water to make 1.5 L of 0.75 M aqueous solution? The molar mass of is
iogann1982 [59]

Answer:

Mass = 65.8 g

Explanation:

Given data:

Mass of sodium chloride = ?

Volume of solution = 1.5 L

Molarity of solution = 0.75 M

Solution:

Number of moles of sodium chloride:

Molarity = number of moles / volume in L

By putting values,

0.75 M = number of moles = 1.5 L

Number of moles = 0.75 M × 1.5 L

Number of moles = 1.125 mol

Mass of sodium chloride:

Mass = number of moles × molar mass

Mass = 1.125 mol × 58.5 g/mol

Mass = 65.8 g

4 0
2 years ago
Pls help I’m in a test plssss
____ [38]

Answer:

6

Explanation:

6

5 0
3 years ago
The OH- concentration in a 2.5 x 10-3 M Ba(OH)2 solution is
zhenek [66]
Answer : C) 5.0 x 10^-3 M
if the concentration of Ba(OH)2 is 2.5 x 10^-3 M

then the OH- concentration is twice this so your answer is C.
4 0
2 years ago
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