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elixir [45]
2 years ago
9

A balloon moving along a straight path experiences a force of

Chemistry
1 answer:
Angelina_Jolie [31]2 years ago
6 0
The net force is 11.1 because 23.5-12.4 is your net force

hope this helps:)
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What is the name of n2o4
quester [9]

Answer:

Dinitrogen tetroxide, commonly referred to as nitrogen tetroxide (NTO), and occasionally (usually among ex-USSR/Russia rocket engineers) as amyl, is the chemical compound N2O4.

8 0
2 years ago
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Find the equation of directrix of the parabola is given by 64x equals to -ySquare ​
ANEK [815]

Answer:

Given equation of parabola is

and

2

=64x ......(i)

The point at which the tangent to the curve is parallel to the line is the nearest point on the curve.

On differentiating both sides of equation (i), we get

2 y

dx

d y

=64

⇒

dx

d y

=

and

32

Also, slope of the given line is −

3

4

∴−

3

4

=

and

32

⇒and=−24

From equation (i), (−24)

2

=64x⇒x=9

∴ the required point is (9,−24)

Explanation:

This is the correct answer you want

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5 0
3 years ago
Which is a characteristic of mixtures?
d1i1m1o1n [39]

Answer: They can be separated by physical processes.

Explanation: A mixture is made up of two or more substances that are not chemically combined and can be easily separated into its constituents by physical methods.

8 0
3 years ago
What do you know about a chemical compound by looking at its chemical formula?
coldgirl [10]
The type of bonds present in the compound. and the type of structure it has and the elements that are presents and the number of moles of each element in one mole of the compound.
4 0
3 years ago
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Suppose a 1.0 L solution contains 0.020 M in Cu(NO3)2, then 0.40 moles of NH3 are added. Assuming no change in volume, what is t
Rasek [7]

Answer:

4.6*10^{-14} M

Explanation:

Concentration of Cu^{2+} = [Cu(NO_3)_2] = 0.020 M

Constructing an ICE table;we have:

                                 Cu^{2+}+4NH_3_{aq} \rightleftharpoons [Cu(NH_3)_4]^{2+}_{(aq)}

Initial (M)             0.020          0.40                        0

Change (M)         -  x                - 4 x                       x

Equilibrium (M)  0.020 -x        0.40 - 4 x              x

Given that: K_f =1.7*10^{13}

K_f } = \frac{[Cu(NH_3)_4]^{2+}}{[Cu^{2+}][NH_3]^4}

1.7*10^{13} = \frac{x}{(0.020-x)(0.40-4x)^4}

Since x is so small; 0.40 -4x = 0.40

Then:

1.7*10^{13} = \frac{x}{(0.020-x)(0.0256)}

1.7*10^{13} = \frac{x}{(5.12*10^{-4}-0.0256x)}

1.7*10^{13}(5.12*10^{-4} - 0.0256x) = x

8.704*10^9-4.352*10^{11}x =x

8.704*10^9 = 4.352*10^{11}x

x = \frac{8.704*10^9}{4.352*10^{11}}

x = 0.0199999999999540

Cu^{2+}= 0.020 - 0.019999999999954

Cu^{2+} = 4.6*10^{-14} M

8 0
2 years ago
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