Answer:
152 kPa = Partial pressure O₂
Explanation:
Data by percent is the molar fraction . 100.
Molar fraction of Helium = 32/ 100 → 0.32
Molar fraction of O₂ = 68/100 → 0.68
Sum of molar fractions in a mixture = 1
0.68 + 0.32 = 1
If we apply the molar fraction, we can determine the partial pressure.
Mole fraction = Partial pressure / Total pressure
0.32 = Partial pressure O₂ / 475kPa → 0.32 . 475 kPa = Partial pressure O₂
152 kPa = Partial pressure O₂
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Answer:
81 molecules
Explanation:
The reaction between C5H12 and O2 is a combustion reaction and is represented by the following equation;
C5H12 + 8O2 --> 5CO2 + 6H2O
The ratio of C5H12 to O2 from the above equation is 1 : 8.
Aplying the conditins of the question; 24 molecules each of C5H12 and O2 we have;
3C5H12 + 24O2 --> 15CO2 + 18H2O
This means we have 24 - 3 = 21 molecules of C5H12 that are unreacted.
Total molecules is given as;
3(C5H12) + 24(O2) + 15(CO2) + 18(H2O) + 21(Unreacted C5H12) = 81 molecules
