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Setler [38]
2 years ago
12

Mass is a measure of weight. A. True B. False

Chemistry
2 answers:
Cerrena [4.2K]2 years ago
6 0

Answer:

A. True

Explanation:

notka56 [123]2 years ago
4 0

Answer: haii~! ur answer is A.) true

Explanation: <u><em>hope dis helps ^^</em></u>

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A cloud that forms near the ground
stiks02 [169]
Hey there!
Great question=)

Answer:Fog, these are clouds that form near the ground.

I hope this helps;)
8 0
3 years ago
Read 2 more answers
If the concentration of Mg2+ in the solution were 0.039 M, what minimum [OH−] triggers precipitation of the Mg2+ ion? (Ksp=2.06×
Elodia [21]

Answer:

2.30 × 10⁻⁶ M

Explanation:

Step 1: Given data

Concentration of Mg²⁺ ([Mg²⁺]): 0.039 M

Solubility product constant of Mg(OH)₂ (Ksp): 2.06 × 10⁻¹³

Step 2: Write the reaction for the solution of Mg(OH)₂

Mg(OH)₂(s) ⇄ Mg²⁺(aq) + 2 OH⁻(aq)

Step 3: Calculate the minimum [OH⁻] required to trigger the precipitation of Mg²⁺ as Mg(OH)₂

We will use the following expression.

Ksp = 2.06 × 10⁻¹³ = [Mg²⁺] × [OH⁻]²

[OH⁻] = 2.30 × 10⁻⁶ M

3 0
4 years ago
If 10 staples have a mass of 1.33 g, what will be the mass of 225 staples?
Leona [35]

Answer:

A) 29.9g

Explanation:

first find the weight of 1 staple.

then multiply with 225

5 0
3 years ago
Read 2 more answers
How many moles of water are produced when 5 moles of hydrogen gas react with 2 moles of oxygen gas?
Marysya12 [62]

4 moles of water are produced

Explanation:

  • 4 moles of water are produced when 5 moles of hydrogen is reacted with 2 moles of oxygen gas
  • The balanced equation given is when 2 moles of hydrogen reacts with 1 mole of oxygen and it forms 2 moles of water.
  • The equation we have to solve is the 5 moles of hydrogen is reacting with 2 moles of oxygen gas, we can write the equation as 5H_{2} +2O_{2} -->  4H_{2} O + H_{2}
  • This is the balanced equation when 5 moles of hydrogen reacts with 2 moles of oxygen. The balanced equation means the number of hydrogen atoms and oxygen atoms on both sides would be equal in number.
4 0
4 years ago
Suppose a system returns to its original overall, internal energy ((∆U) after the following changes. In step 1, 25 J of work is
Brums [2.3K]

Answer:

Heat transfer in step 2 = 47.75 J

Explanation:

Internal energy = heat + work done

U = Q + W

In a cyclic process the total internal energy change of the system = 0.

In the process there are two steps. The total heat exchange in the process is the sum of heat exchanges in the two processes.

We have to find the heat exchange in step 2.

In step 1,

W = 1.25 J          Q = -37 J

U_{1} = -37 + 1.25 = -35.75 J

In step 2, the internal energy change will be negative of that in step 1.

U = 35.75 J

W = -12 J

U = Q + W

35.75 = Q -12

Q = 47.75 J

Heat transfer in step 2 = 47.75 J

6 0
4 years ago
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