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3 years ago

What is the best classification for this sample of crude oil?

Chemistry

2 answers:

Nata [24]3 years ago

6 0

Its have a classification of light and heavy crude oil

Makovka662 [10]3 years ago

5 0

A crude oil is a mixture of different hydrocarbons found in it. It is also commonly known as petroleum. It is made by compressing and heating organic matter for a long time period. The four main kinds of hydrocarbons located in crude oil are paraffins, naphthenes, aromatics and asphaltics.

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Which of the following explanations accounts for the fact that the ion-solvent interaction is greater for Li than for K

OLEGan [10]

Li+ has a smaller ionic radius than K+

and smaller molecules have more collisions/interactions between each other

<h3>What is ion-solvent interaction ?</h3>

In the case of ion-solvent interactions, the state in which the interac-tions exist is an obvious one; it is the situation in which ions are inside the solvent.

Ions are charged particles, and charges interact with other charges. So there will also be ion-ion, as well as ion-solvent, interactions in the solution.

In the process of solvation, ions are surrounded by a concentric shell of solvent. Solvation is the process of reorganizing solvent and solute molecules into solvation complexes.

Learn more about Ion-solvent interaction here:

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6 0

1 year ago

In compounds,has an oxidation number 1-

alex41 [277]

Fluorine in compounds is always assigned an oxidation number of -1

5 0

3 years ago

1) How much water must be added to 500.mL of 0.200 M HCI to produce a 0.150M solution?

zloy xaker [14]

Answer:

(500.mL)(.200M)/.150M = 667 mL

667mL - 500mL = 167mL of water is needed

1.0 L = 1000mL

M1 V1 = M2 V2

(1.6 mol/L) (175 mL) = (x)(1000mL)

x = .28M

6 0

3 years ago

what would the molarity of a solution be if you took 10 mL of a 13M stock solution and made a 300 mL solution?

nignag [31]

Answer:

0.43M

Explanation:

8 0

3 years ago

Based on the three formulas shown, use one of them to solve for the purple yellow and red box and explain how you did it.

zysi [14]

P = 11.133 atm (purple)

T = -236.733 °C(yellow)

n = 0.174 mol(red)

<h3>Further explanation </h3>

Some of the laws regarding gas, can apply to ideal gas (volume expansion does not occur when the gas is heated),:

Boyle's law at constant T, P = 1 / V
Charles's law, at constant P, V = T
Avogadro's law, at constant P and T, V = n

So that the three laws can be combined into a single gas equation, the ideal gas equation

In general, the gas equation can be written

$\large {\boxed {\bold {PV = nRT}}}$

where

P = pressure, atm

V = volume, liter

n = number of moles

R = gas constant = 0.08206 L.atm / mol K

T = temperature, Kelvin

To choose the formula used, we refer to the data provided

Because the data provided are temperature, pressure, volume and moles, than we use the formula PV = nRT

Purple box

T= 10 +273.15 = 373.15 K

V=5.5 L

n=2 mol

$\tt P=\dfrac{nRT}{V}\\\\P=\dfrac{2\times 0.08205\times 373.15}{5.5}\\\\P=11.133~atm$

Yellow box

V=8.3 L

P=1.8 atm

n=5 mol

$\tt T=\dfrac{PV}{nR}\\\\T=\dfrac{1.8\times 8.3}{5\times 0.08205}\\\\T=36.42~K=-236.733^oC$

Red box

T = 12 + 273.15 = 285.15 K

V=3.4 L

P=1.2 atm

$\tt n=\dfrac{PV}{RT}\\\\n=\dfrac{1.2\times 3.4}{0.08205\times 285.15}\\\\n=0.174~mol$

3 0

3 years ago