There are approximately 160 grams in 1 mol of Fe2O3 molecules. Therefore, there would be 79/160= 0.49375 mols of Fe2O3 molecules in 79 grams. There are 5 atoms in total for each molecule of Fe2O3, therefore 79/160 * 5 = 79/32 = 2.46875 mols of atoms.
Answer:
1.67mol/L
Explanation:
Data obtained from the question include:
Mole of solute (K2CO3) = 5.51 moles
Volume of solution = 3.30 L
Molarity =?
Molarity is simply the mole of solute per unit litre of the solution. It can be expressed mathematically as:
Molarity = mole of solute /Volume of solution
Molarity = 5.51 mol/3.30 L
Molarity = 1.67mol/L
Therefore, the molarity of K2CO3 is 1.67mol/L
The average weight of an atom of an element, formerly based on the
weight of one hydrogen atom taken as a unit or on 1/16 (0.0625) the
weight of an oxygen atom, but after 1961 based on 1/12 the weight of the
carbon-12 atom.
Using the stoichiometry of the reaction and the information provided in the question, the mass of N2 used is 11.62 g.
<h3>Chemical reaction</h3>
The term chemical reaction refers to the combiantion of two or substances to yiled one or more products. The reaction equation in this case is N2 + O2 --->2NO.
Now;
Number of moles of NO = 25g/30 g/mol = 0.83 moles
1 mole of N2 yields 2 moles of NO
x moles of N2 yileds 0.83 moles of NO
x = 0.415 moles
Mass of N2 = 0.415 moles * 28 g/mol = 11.62 g
Learn more about stoichiometry:
brainly.com/question/12166462
