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3 years ago

What is the best classification for this sample of crude oil?

Chemistry

2 answers:

Nata [24]3 years ago

6 0

Its have a classification of light and heavy crude oil

Makovka662 [10]3 years ago

5 0

A crude oil is a mixture of different hydrocarbons found in it. It is also commonly known as petroleum. It is made by compressing and heating organic matter for a long time period. The four main kinds of hydrocarbons located in crude oil are paraffins, naphthenes, aromatics and asphaltics.

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In a study designed to prepare new gasoline-resistant coatings, a polymer chemist dissolves 6.143 g poly(vinyl alcohol) in enoug

Ghella [55]

Answer:

MM = 5,521.54 g/mol

Explanation:

To solve this, we need to use the expression for osmotic pressure which is the following:

π = MRT (1)

Where:

M: Concentration of the solution

R: gas constant (0.082 L atm/ mol K

T: temperature in K

25 °C in Kelvin is: 25 + 273.15 = 298.15 K

Now, we do not have the concentration of the solution, but we do have the mass. and the concentration can be expressed in terms of mass, molar mass and volume:

Concentration (M) is:

M = n/V (2)

and n (moles) is:

n = m/MM (3)

Therefore, if we replace (2) and (3) in (1) we have:

π = mRT/V*MM

Solving for MM we have:

MM = mRT/πV (4)

All we have to do now, is replace the given data and we should get the value of the molar mass:

MM = 6.143 * 0.082 * 298.15 / 0.1 * 0.272

MM = 150.1859 / 0.0272

MM = 5,521.54 g/mol

This is the molar mass.

7 0

3 years ago

In the laboratory a student determines the specific heat of a metal. He heats 19.5 grams of copper to 98.27 °C and then drops it

siniylev [52]

Answer:

The specific heat of copper is 0.37 J/g°C

Explanation:

Step 1: Data given

Mass of copper = 19.5 grams

Initial temperature of copper = 98.27 °C

Mass of water = 76.3 grams

Initial temperature of water = 24.05 °C

Final temperature of water and copper = 25.69 °C

Step 2: Calculate specific heat of copper

Qgained = -Qlost

Q = m*c*ΔT

Qwater = -Qcopper

m(water) * c(water) * ΔT(water) = - m(copper) * c(copper) *ΔT(copper)

⇒ with m(water) = 76.3 grams

⇒ with c(water) = 4.184 J/g°C

⇒ with ΔT(water) = T2-T1 = 25.69 - 24.05 = 1.64

⇒ with m(copper) = 19.5 grams

⇒ with c(copper) = TO BE DETERMINED

⇒ with ΔT(copper) = T2-T1 = 25.69 - 98.27 = -72.58

76.3 * 4.184 * 1.64 = - 19.5 * c(copper) * -72.58

523.552 = 1415.31 * c(copper)

c(copper) = 0.37 J/g°C

The specific heat of copper is 0.37 J/g°C

3 0

4 years ago

When H+ forms a Bond with H2O to form the Hydronium ion H3 plus this bond is called a coordinate covalent bond because

NISA [10]

Answer:

Because both the bonding electrons come from the oxygen atom. Explanation: A coordinate covalent bond is formed when both the bonding electrons are coming from the same atom

Explanation:

7 0

3 years ago

Hydrogen peroxide (H202) is a compound made from two elements: hydrogen and oxygen. Water(H20) is also a compound made from hydr

MrRissso [65]

one is air and the other is a liquid

7 0

3 years ago

What are the amplitude's for both waves A and B?

Bad White [126]

Answer:

Wave A= 20m

Wave B= 30m

Explanation:

The amplitude of a wave is the maximum displacement (or height) from its equillibrum position.

The equilibrium position is at 0 meters for both waves.

Thus, amplitude of wave A= 20m

Amplitude of wave B= 30m

5 0

3 years ago