Answer:
Ix = Iy = 
Radius of gyration x = y = 
Step-by-step explanation:
Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.
Mass of disk = ρπR2
Moment of inertia about its perpendicular axis is 
. Moment of inertia of quarter disk about its perpendicular is 
.
Now using perpendicular axis theorem, Ix = Iy = 
= .
For Radius of gyration K, equate MK2 = MR2/16, K= R/4.
(The answer is 12.082.) Juan used 12.082 meters of rope.
Answer:
4
Step-by-step explanation:
Hope this helps!! Have a good day!
X=8
Set up proportions would give you: 10/3x+1 = 22/7x-1
With that in mind, cross multiply, which would give you: 10(7x-1) = 22(3x+1).
Turns into: 70x -10 = 66x+22. Then just solve for x
A-length
b-width
perimeter of rectangular floor: 2a+2b=204
<span>The length is two times the width: a=2b
</span>2a + 2b = 204
2*2b + 2b = 204
6b = 204|:6
b = 34
a=2b=2*34=68
a=68->length
b=34->width
