Answer:
17.7 cm^2
Step-by-step explanation:
Use trig to find the height of the triangle. Then the area is bh/2.
Extend side BC to the right until it is vertically below point A. Draw a segment from point A vertically down until it intersects the extension of side BC. Call the point of intersection D. <D is a right angle.
Use triangle ABD to find the height, AD, of triangle ABC.
For <B of 37 deg, AD is the opposite leg. AB is the hypotenuse. The trig ratio that relates the opposite lefg to the hypotenuse is the sine.
sin B = opp/hyp
sin 37 deg = AD/13.1
AD = 13.1 * sin 37 deg
AD = 7.9
AD is the height of triangle ABC. BC is the base. We can find the area of triangle ABC.
area = bh/2
area = (4.5 cm)(7.9 cm)/2
area = 17.7 cm^2
So increased weight = 92-80 = 12
so ℅ = 12×100/80 = 15
so his weight is increased by 15℅ !!
4(x+5)+6=2(2x+3)
4x+20+6=4x+6
4x+26=4x+6
Get letters on left...so subtract 4x from right and do same to left
26=6
no solution because 26 does not equal 6
Answer:
D
Step-by-step explanation:
Because in D, there no x-value that are repeating in the list.
For example A, the value 8 and -8 are being repeated twice, which makes this relation not a fuction.
Answer:
The distance between 4 and 7 is : 3
