Answer:
Step-by-step explanation:
i assume x+y=6(1/2)=\frac{13}{2}
Not me
Step-by-step explanation:
I am not certain of what you wrote for the function but will assume that is likely exponential function or quadratic function.
First, (quadratic function) To solve this, you must know the quadratic formula. The x-intercept is value(s) that has the output value(y) of 0.
If the vertex of the quadratic function of (0,0), there is only one x-intercept. The number and value of the x-intercept depends on the slope and vertical displacement.
Second, (exponential function) note that there is no x-intercept. For instance, if a is 2, is there such value y that 2^y is 0? The smallest exponential value that is an integer is 1. Even broadening the limit to rational numbers, no such exponential value can have the result of 0. Therefore, in the basic form of exponential function, there is no x-intercept.
Answer:
D. y=70x
Step-by-step explanation:
The cheetah was clocked running 70 miles per hour.
i.e. in 1 hour cheetah covered 70 miles
in 2 hours cheetah covered 140 miles
in 3 hours cheetah covered 210 miles
in general, in n hour cheetah covered 70n miles
If y denote the distance covered
and x denotes the time cheetah runs
Then, y=70x
Hence, the equation which shows the relationship between the distance, y, and time, x, the cheetah runs is:
D y=70x
The best way to solve this problem is with a simple equation: part = percent (in decimal form) x whole
In this problem, we're trying to solve for the <em>whole </em>amount that the camera can hold, so we'll assign that the variable w.
We can use the information they gave us - 96 is the <em>part</em>, and 24% is the percent. We'll convert that to decimal form - 0.24
Then, we just plug these values back into the above equation:
96 = 0.24w
Divide both sides by 0.24 to get w on it's own, and you have your answer!
400 = w
Therefore, the memory card can hold up to 400 pictures.
Note: this equation is <em>super </em>helpful. It's good to have on hand for any problem involving percents, because you can solve for the part, percent, or whole depending on the problem.
