All categories

3 years ago

What factors can cause an induced current in a wire loop through which a magnetic field passes?.

1 answer:

7 0

The factors that can cause an induced current in a wire loop are number of turns of the wire, area of the wire and magnetic field strength.

<h3>Induced emf</h3>

According to Faraday's law of electromagnetic induction, the rate of change of flux in a magnetic field is proportional to the flux through the magnetic field.

emf = dФ/dt

where;

Ф is magnetic flux = BA (magnetic field and area of the coil)

emf = N(BA)/dt

where;

N is number of turns

Thus, the factors that can cause an induced current in a wire loop are number of turns of the wire, area of the wire and magnetic field strength.

Learn more about electromagnetic induction here: brainly.com/question/26334813

You might be interested in

Please help me with these I might need more than only 1 person to answer

Sindrei [870]

Explanation:

a) copper

b) olive oil

Hope it helps✌✌

7 0

3 years ago

What is the relationship in which the ratio of the manipulated variable and the responding variable is constant?

son4ous [18]

That's a 'direct' or 'proportional' variation.

The variables are related by the equation Y = K X .

That constant ratio is the number ' K ' .

5 0

3 years ago

An object travels a given distance at a speed of 5 m/s. If the object travels the same distance at a higher speed, how will the

OverLord2011 [107]

a. it will take less time

4 0

4 years ago

Read 2 more answers

A 50-V de voltage source was connected in series with a resistor and capacitor. Calculate the current in A to two significant fi

Naddik [55]

Answer:

Current through circuit will be $0.2706\times 10^6A$

Explanation:

We have given source voltage v = 50 volt

Resistance $R=25Mohm=25\times 10^6ohm$

Capacitance $C=0.1\mu F=0.1\times 10^{-6}F$

Time t = 5 sec

Time constant of RC circuit is given by $\tau =RC=25\times 10^6\times 0.1\times 10^{-6}=2.5sec$

We know that voltage across capacitor is given by $v_c=v_s(1-e^{\frac{-t}{\tau }})$

$v_c=50(1-e^{\frac{-5}{2.5 }})=43.2332v$

So current will be $=\frac{v_s-v_c}{R}=\frac{50-43.2332}{25\times 10^{-6}}=0.2706\times 10^6A$

So current through circuit will be $0.2706\times 10^6A$

4 0

4 years ago

A car speedometer that is supposed to read the linear speed of the car uses a device that actually measures the angular speed of

nikklg [1K]

When a car<span> rounds a corner at a constant </span>speed<span>, its acceleration is zero. Suppose you are in a </span>car<span> that is going around a curve. The speedometer reads a constant 30 miles per hour. ... </span>Describe the speed<span> of the object from 4-6 seconds using the distance vs. time graph.</span>

4 0

3 years ago