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r-ruslan [8.4K]
3 years ago
10

Help pls sand quickly plssssss

Physics
2 answers:
tamaranim1 [39]3 years ago
6 0

Answer:

The magnet produces an electric current in the wire

Explanation:

hjlf3 years ago
6 0

Answer: the first one is right

Explanation:

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What condition is necessary for the flow of heat? What analogous condition is necessary for the flow of charge?
cricket20 [7]
Temperature difference; voltage difference
6 0
4 years ago
A force of 100.0N is appliesd to an object of mass 85.0kg. what is the object acceleration
kumpel [21]

Answer:

<h2>1.18 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{100}{85}  =  \frac{20}{17}  \\  = 1.176470...

We have the final answer as

<h3>1.18 m/s²</h3>

Hope this helps you

3 0
3 years ago
How much kinetic energy is required to break through?
Ksju [112]

Explanation:

The natural environment or natural world encompasses all living and non-living things occurring naturally, meaning in this case not artificial. The term is most often applied to the Earth or some parts of Earth

7 0
3 years ago
Two polarizers A and B are aligned so that their transmission axes are vertical and horizontal, respectively. A third polarizer
Reptile [31]

Answer:

Explanation:

Let the angle between the first polariser and the second polariser axis is θ.

By using of law of Malus

(a)

Let the intensity of light coming out from the first polariser is I'

I' = I_{0}Cos^{2}\theta     .... (1)

Now the angle between the transmission axis of the second and the third polariser is 90 - θ. Let the intensity of light coming out from the third polariser is I''.

By the law of Malus

I'' = I'Cos^{2}\left ( 90-\theta \right )

So,

I'' = I_{0}Cos^{2}\theta Cos^{2}\left ( 90-\theta \right )

I'' = I_{0}Cos^{2}\theta Sin^{2}\theta

I'' = \frac{I_{0}}{4}Sin^{2}2\theta

(b)

Now differentiate with respect to θ.

I'' = \frac{I_{0}}{4}\times 2 \times 2 \times Sin2\theta \times Cos 2\theta

I'' = \frac{I_{0}}{2}\times Sin 4\theta

7 0
4 years ago
Chris and Jamie are carrying Wayne on a horizontal stretcher. The uniform stretcher is 2.00 m long and weighs 100 N. Wayne weigh
BabaBlast [244]

Answer:

<h2>E. 650N</h2>

Explanation:

step one:

given

length of stretcher= 2m

weight of stretcher=100N

Wayne weighs =800N

distance of Wayne weighs from chris's end= 75cm= 0.75m

The force that Chris is exerting to support the stretcher, with Wayne on it, can be computed by taking moments of the weight of the stretcher and Wayne weighs  about Chris's end, the end result is the reaction at Chris's end

Taking moment about Chris's end

The moment of Wayne weight 75cm from Chris+ Half the weight of stretcher 1m from Chris

0.75*800+50*1=0

600+50=0

650N

6 0
3 years ago
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