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Maurinko [17]
3 years ago
11

Without understanding mathematics, it is practically impossible to see its applicability and beauty

Physics
1 answer:
Kamila [148]3 years ago
4 0

True

Explanation:

In order to apply and experience the beauty of mathematics, a good comprehension of the discipline is required.

In fact, this is general to anything in life. To fully maximize any potential, one must be well groomed about what exactly that thing is.

Mathematics is a science that deals with the logic of shapes and numbers. There are different branches of this discipline with real world adoption.

The tenets of mathematics cuts across business, science, arts, e.t.c.

Learn more:

Statistics brainly.com/question/6356614

#learnwithBrainly

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A 7.7 kg sphere makes a perfectly inelastic collision with a second sphere initially at rest. The composite system moves with a
klemol [59]

Answer:

15.4 kg.

Explanation:

From the law of conservation of momentum,

Total momentum before collision = Total momentum after collision

mu+m'u' = V(m+m').................... Equation 1

Where m = mass of the first sphere, m' = mass of the second sphere, u = initial velocity of the first sphere, u' = initial velocity of the second sphere, V = common velocity of both sphere.

Given: m = 7.7 kg, u' = 0 m/s (at rest)

Let: u = x m/s, and V = 1/3x m/s

Substitute into equation 1

7.7(x)+m'(0) = 1/3x(7.7+m')

7.7x = 1/3x(7.7+m')

7.7 = 1/3(7.7+m')

23.1 = 7.7+m'

m' = 23.1-7.7

m' = 15.4 kg.

Hence the mass of the second sphere = 15.4 kg

7 0
3 years ago
Read 2 more answers
Two dump trucks each have a mass of 1,500 kg. The distance of the dump truck
xxTIMURxx [149]

Answer:

6.00 x 10⁻⁸N

Explanation:

Given parameters:

Mass of each dump trucks  = 1500kg

Distance between them  = 50m

Unknown:

New gravitational force between them = ?

Solution:

From Newton's law of universal gravitation,

        F = \frac{G m1 m2}{r^{2} }  

F is the gravitational force

G is the universal gravitation constant

m is the mass

r is the distance

           F  = \frac{6.67 x 10^{-11} x 1500  x 1500}{50^{2} }    = 6.00 x 10⁻⁸N

4 0
3 years ago
Jen pushed a box for a distance of 80m with 20 N of force. How much work did she do?
Drupady [299]
The answer is 1,600 J.

A work (W) can be expressed as a product of a force (F) and a distance (d):
W = F · d<span>

We have:
W = ?
F = 20 N = 20 kg*m/s</span>²
d = 80 m
_____
W = 20 kg*m/s² * 80 m
W = 20 * 80 kg*m/s² * m
W = 1600 kg*m²/s²
W = 1600 J
8 0
3 years ago
Can someone please help me! BRAINLIEST ANSWER! What happens after the Gulf Stream travels north?
Irina-Kira [14]
A should be the answer since it makes the water down there cold and the air also. (asked my grandma haha
3 0
3 years ago
A hotel wants to put a fence around a circular spa. The radius of the spa is 5/√2-1 feet. If the fence is built along the immedi
Vlad [161]
It is important to look at all the information's that are given in the question very closely. Let us write them write first.

Radius of the spa = <span>5/√2-1 feet
Now
Perimeter of the circle = </span><span>2πr
                                    = 2</span>π (5/√2-1) 
                                    = <span>π(5/(√2-1)*(√2+1)/(√2+1) </span>
<span>                                    = 2π(5/(√2+1))/(2-1) </span>
<span>                                    = 10π(√2+1)  

I hope that the procedure is clear enough for you to understand.</span>
5 0
3 years ago
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