All categories

2 years ago

True or false: When your ear detects sound, there is an actual collision of particles from the sound wave that hit your ear drum

Physics

2 answers:

balandron [24]2 years ago

7 0

Answer:

True...

Explanation:

When these high amplitude vibrations impinge upon the eardrum, they produce a very forceful displacement of the eardrum from its rest position. The ear's ability to do this allows us to perceive the pitch of sounds by detection of the wave's frequencies, the loudness of sound by detection of the wave's ...

When the sound waves hit your eardrum, they cause it to vibrate—the same way that a real drum vibrates when you hit it with a drumstick. The vibrations in your eardrum are then transferred via three tiny bones inside your ear into a fluid-filled chamber called the cochlea (pronounced KOK-lee-uh).

VashaNatasha [74]2 years ago

4 0

Answer:

True: For a sound wave to propagate, air particles must be displaced in the direction of propagation - it is the displacement of these particles that causes the eardrum to vibrate and recognize the sound.

You might be interested in

A ping-pong ball is traveling at 10m/s in air, spinning 100 revolutions per second in the clockwise direction. Calculate the lif

allsm [11]

Answer:

lift force = 0.213 N

Drag force = $2*10^-3 N$

Explanation:

Given: velocity v = 10 m/s

w = 100 rev/sec

diameter d = 3cm

density D = 1.2kg/m3

lift force = $16/3*(pi^2*d^3*w*D*v)$

Substituting the values into the equation, we obtain

lift force = 0.213 N

Drag force = C*D*A*v/2

where C = 0.5

substituting the values into the equation again, we have

Drag force = $2*10^-3 N$

5 0

3 years ago

I need help in this small question:

Natali5045456 [20]

Answer:

1) The energy released during nuclear fission or fusion, especially when used to generate electricity is called nuclear energy.

2) It is not renewable because it is an element that has no way whatsoever to regenerate or replicate itself, nor gets created by any natural terrestrial means, neither makes itself available by arriving from outer space (like sunlight). There is a limited amount of it available on the Earth, and every bit you use is a bit you’ll never have available again (as Uranium atoms get destroyed by the fission process).

Hope this helps You

Please mark as brainliest

Thank You

5 0

3 years ago

During a firework display, a shell is shot through the air with an initiak speed of 70 m/s at an angle of 75° above the horizont

ladessa [460]

Answer:

241.24m

Explanation:

The height at which the shell explodes will be at the maximum height. In projectile motion, maximum height formula is expressed as:

H = u²sin²θ/2g

u is the initial speed = 70m/s

θ the angle of launch = 75°

g is the acceleration due to gravity = 9.81m/s²

Substitute the values into the formula and get H

H = 70²(sin75°)/2(9.81)

H = 4900sin75°/19.62

H = 4900*0.9659/19.62

H = 4733.037/19.62

H = 241.24m

Hence the height at which the shell explodes is 241.24m

4 0

3 years ago

I NEED HELP ASAP! BRAINIEST TO THE CORRECT ANSWER. HELP ME NOW!

sergij07 [2.7K]

Answer:

$\boxed{\mathfrak{Power(P)=\frac{Voltage(V)^2}{Resistance(R)} }}$

V = 12 V
P = 24 W

$\implies \mathsf{24=\frac{12^2}{R} }$

$\implies \mathsf{24R=12^2 }$

$\implies \mathsf{24R=144 }$

$\boxed{\mathfrak{Power(P)=\frac{Voltage(V)^2}{Resistance(R)} }}$

Power (P)= 100 W

<em>these lights operate at the usual 240 volts direct from the main electricity supply. Therefore,</em>

V = 240 V

$\implies \mathsf{100=\frac{240^2}{R} }$

<em>R and 100 can interchange places</em>

$\implies \mathsf{R=\frac{240^2}{100} }$

$\implies \mathsf{R=\frac{57600}{100} }$

<u></u>

By Ohm's Law:

$\boxed{\mathsf{Voltage(V)=Current(I) \times Resistance(R)}}$

=> 240 = I × 576

=> I = 0.417 A

I don't know it's resistance,... so sorry

The brightness of the bulb in series is <em><u>less than</u></em> when they're placed individually.

For bulbs in series their resistance gets added to form the equivalent resistance of the two bulbs.

Their resistances are nothing but mere numbers and the sum of two numbers(positive of course) is greater than the numbers.

So, the effective resistance of some bulbs in series <u>is more</u> than the individual resistance.

And

<em>Brightness, i. e., Power</em>

$\boxed{\mathfrak{Power \propto \frac{1}{Resistance} }}$

If resistance increases, Power decreases.

Here, the effective resistance was for sure larger, therefore resistance was increasing, hence power decreased taking brightness along with it.

3 0

3 years ago

Which tools collect images during space exploration? Check all that apply. rovers orbiters satellites space shuttles space stati

grigory [225]

Answer:

1. Rovers- These are vehicles which are designed to move on the surface on any celestial body and collect samples, data and images. Sometimes, these can be used to transport mission crew members.

2. Orbiters- These are spacecrafts designed to orbit any celestial body and collect data in form of images.

3. satellites- artificial satellites are placed in the orbit of celestial bodies for various purposes. There are various types of satellites like communication satellite, weather satellites, space telescopes. These collect images and data inform of signals.

4. space stations: It is a satellite where research and experiments take place. Images are also collected for research purpose.

Space shuttle is a wrong option because it is just a vehicle to transport these satellites and probes into the space and place in the orbit or surface of celestial body.

4 0

4 years ago

Read 2 more answers