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icang [17]
2 years ago
14

True or false: When your ear detects sound, there is an actual collision of particles from the sound wave that hit your ear drum

Physics
2 answers:
balandron [24]2 years ago
7 0

Answer:

True...

Explanation:

When these high amplitude vibrations impinge upon the eardrum, they produce a very forceful displacement of the eardrum from its rest position. The ear's ability to do this allows us to perceive the pitch of sounds by detection of the wave's frequencies, the loudness of sound by detection of the wave's ...

When the sound waves hit your eardrum, they cause it to vibrate—the same way that a real drum vibrates when you hit it with a drumstick. The vibrations in your eardrum are then transferred via three tiny bones inside your ear into a fluid-filled chamber called the cochlea (pronounced KOK-lee-uh).

VashaNatasha [74]2 years ago
4 0

Answer:

True: For a sound wave to propagate, air particles must be displaced in the direction of propagation - it is the displacement of these particles that causes the eardrum to vibrate and recognize the sound.

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A block slides down a frictionless plane that makes an angle of 24.0° with the horizontal. What is the
irga5000 [103]

Answer:

F = m g sin theta      force accelerating block

m a = m g sin theta

a = 9.8 sin 24 = 3.99 m/sec^2

7 0
3 years ago
Calculate the force of gravity between a 2.50 kg newborn baby and a 80.0 kg doctor standing 0.250 m away. G = 6.67 E -11 N*m2/kg
Alex787 [66]

Answer: 2.13 × 10⁻⁷ N

Explanation:

Gravitational force exists between any two bodies having mass.

Force of gravity is given by:

F =G\frac{Mm}{r^2}

It is given that, mass of newborn baby is M = 2.50 kg

Mass of the doctor, m = 80.0 kg

Distance between the two, r = 0.250 m

Gravitational constant, G = 6.67 × 10⁻¹¹ N m²/kg²

⇒F = (6.67 × 10⁻¹¹ N m²/kg² × 2.50 kg × 80.0 kg )÷ (0.250 m)² = 2.13 × 10⁻⁷ N

Thus, the force of gravity between new born baby and doctor is 2.13 × 10⁻⁷ N.

7 0
3 years ago
during a lunar mission, it is necessary to increase the speed of a spacecraft by 2.2 m/s when it is moving at 400 m/s relative t
wel

The initial mass fraction of the spacecraft that must be burned and ejected to achieve an increase in speed is 0,00219 m/s

<h3>What fraction of the initial mass of the spacecraft?</h3>

Increase the speed: Vf-Vi = 2.2 m/s

Speed of aircraft: Vr = 400 m/s

Speed of ejected products: Vrel = 1000 m/s

The answer is:

V_f - V_i = V_{rel} log_{e} (\frac{mi}{mf})\\\\2.2 = 1000 log_{e} (\frac{mi}{mf})\\\\ log_{e} (\frac{mi}{mf} ) = \frac{2.2}{1000} \\\\ log_{e} (\frac{mi}{mf} ) = 0.0022

\frac{mi}{mf} = e^{0,0022} \\\\\frac{mf}{mi} = e^{-0,0022} \\\\\frac{mi-mf}{mi} = 1 - e^{-0,0022} = 0,00219

So, the initial mass fraction of the spacecraft that must be burned and ejected to achieve an increase in speed is 0,00219 m/s

Learn more about spaceship speed fraction brainly.com/question/28256735

#SPJ4

3 0
1 year ago
Describe how the three methods of thermal energy transfer may take place within the iguana’s enclosure.
sasho [114]

Answer:

Heat can travel from one place to another in three ways: Conduction, Convection and Radiation. Both conduction and convection require matter to transfer heat.  Conduction is the transfer of heat between substances that are in direct contact with each other. Thermal energy is transferred from hot places to cold places by convection. Radiation is a method of heat transfer that does not rely upon any contact between the heat source and the heated object as is the case with conduction and convection. Heat can be transmitted through empty space by thermal radiation often called infrared radiation.

Explanation:

6 0
2 years ago
Read 2 more answers
Suppose a plane accelerates from rest for 30 s, achieving a takeoff speed of 80 m/s after traveling a distance of 1200 m down th
Margaret [11]

Answer:

300 m

Explanation:

The train accelerate from the rest so u = 0 m/sec

Final speed that is v = 80 m/sec

Time t = 30 sec

The distance traveled by first plane = 1200 m

We know the equation of motion S=ut+\frac{1}{2}at^2 where s is distance a is acceleration and u is initial velocity

Using this equation for first plane 1200=0\times 30+\frac{1}{2}a30^2

a=2.67\frac{m}{sec^2}

As the acceleration is same for both the plane so a for second plane will be 2.67 \frac{m}{sec^2}

The another equation of motion is v^2=u^2+2as using this equation for second plane 40^2=0+2\times 2.67\times s

s = 300 m

5 0
3 years ago
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