The doppler effect is the increase or decrease in the frequency of sound, light, or other waves as the source and observer move toward or away from each other.
Assuming constant acceleration, the goalie slows the ball from 18 m/s to rest in 0.035 s, so that the acceleration felt by the ball is
![a_{\rm ave} = a = \dfrac{18\frac{\rm m}{\rm s}-0}{0.035\,\mathrm s} \approx \boxed{510\dfrac{\rm m}{\mathrm s^2}}](https://tex.z-dn.net/?f=a_%7B%5Crm%20ave%7D%20%3D%20a%20%3D%20%5Cdfrac%7B18%5Cfrac%7B%5Crm%20m%7D%7B%5Crm%20s%7D-0%7D%7B0.035%5C%2C%5Cmathrm%20s%7D%20%5Capprox%20%5Cboxed%7B510%5Cdfrac%7B%5Crm%20m%7D%7B%5Cmathrm%20s%5E2%7D%7D)
<u><em>Answer:</em></u>
The answer is 1400 J, according to my Physics teacher.
<u><em>Explanation:</em></u>
You need to take into account everything that is listed in the question; it's important to remember that the question is asking about the change in gravitational potential energy of the object-object-Earth system from 0s to 10s, not 0s to 20s. :)
Hydra would not be considered a dwarf planet. Hydra is a moon of Pluto.
Answer:
165.77J
Explanation:
M₁ = 0.107kg
u₁ = 300m/s
m₂ = 3kg
u₂ = 0
v =
m₁u₁ + m₂u₂ = (m₁ + m₂)V
(0.107*300) + 0 = (0.107 + 3)V
V = 32.1 / 3.107 = 10.33m/s
kinetic energy of the system after collision =
½m1v² + ½m2v²
K.E = ½(m1 + m2)v²
K.E = ½(0.107+3) * 10.33²
K.E = 165.77J