Answer: 
Explanation:
The rest of the question is below:
Find a2, the magnitude of the centripetal acceleration of the star with mass m2.
Assuming both stars are describing a uniform circular motion, their acceleration vector is directed towards the center of mass of the system (that's why it's called centripetal acceleration).
Now, according to Newton's 2nd law, the force
is directly proportional and in the same direction as the acceleration.
For
:
For
:
If the centripetal force is the same for both stars:
Isolating
:

Every outlet, receptacle, lamp, appliance, and other directly wired device in the house must all be connected in parallel.
-- This ensures that each receptacle and light socket is supplied the same voltage.
-- It also ensures that turning off or unplugging one device won't cut off the power to a bunch of others in the house.
Given Data: Diameter 'd' = 30 cm = 0.3 m Lifting Weight 'W' = mg = 2000*9.81 N = 19,620 N Calculations: Area of the lift 'A' = <span>pi\over4*d^2=pi\over4*0.3^2=0.07 m^2
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Therefore, the magnitude of magnetic field at a distance 1.10cm from the origin is 27.3mT
<u>Explanation:</u>
Given;
Number of turns, N = 1000
Inner radius, r₁ = 1cm
Outer radius, r₂ = 2cm
Current, I = 1.5A
Magnetic field strength, B = ?
The magnetic field inside a tightly wound toroid is given by B = μ₀ NI / 2πr
where,
a < r < b and a and b are the inner and outer radii of the toroid.
The magnetic field of toroid is

Substituting the values in the formula:


Therefore, the magnitude of magnetic field at a distance 1.10cm from the origin is 27.3mT
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