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2 years ago

How many meters are in one yard? 1m=1.09

Chemistry

2 answers:

GuDViN [60]2 years ago

4 0

Answer:

0.9144, hoped I helped

Darina [25.2K]2 years ago

3 0

0.91 meters are in one yard. If you wouldn’t mind I only need 2 more brainliests

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Which element would be the most reactive with K? Br, Na, Ar, or O? And how do you know?

kykrilka [37]

Ar I did this I think i got it right on edunuty

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2 years ago

Which of the following elements is represented by the orbital diagram?

aalyn [17]

The answer is A I hope it was right

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3 years ago

Afirmar que el h20 es la formula que corresponde al agua, esto es una teoría, idea, ley, hipotesis o experimentación

frozen [14]

Answer:

Ley.

Explanation:

En la teoría de la ciencia, la regularidad de los procesos en la naturaleza se denomina ley de la naturaleza. Las leyes naturales se diferencian de otras leyes en que los seres humanos no pueden ponerlas en vigor ni anularlas a su discreción. En tal sentido, la composición química del agua es indudablemente una ley natural, en tanto el hombre no puede modificarla sin modificar las características inherentes del agua como tal.

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2 years ago

. Determine the standard free energy change, ɔ(G p for the formation of S2−(aq) given that the ɔ(G p for Ag+(aq) and Ag2S(s) are

olga nikolaevna [1]

Answer: The standard free energy change of formation of $S^{2-}(aq.)$ is 92.094 kJ/mol

Explanation:

We are given:

$K_{sp}\text{ of }Ag_2S=8\times 10^{-51}$

Relation between standard Gibbs free energy and equilibrium constant follows:

$\Delta G^o=-RT\ln K$

where,

$\Delta G^o$ = standard Gibbs free energy = ?

R = Gas constant = $8.314J/K mol$

T = temperature = $25^oC=[273+25]K=298K$

K = equilibrium constant or solubility product = $8\times 10^{-51}$

Putting values in above equation, we get:

$\Delta G^o=-(8.314J/K.mol)\times 298K\times \ln (8\times 10^{-51})\\\\\Delta G^o=285793.9J/mol=285.794kJ$

For the given chemical equation:

$Ag_2S(s)\rightleftharpoons 2Ag^+(aq.)+S^{2-}(aq.)$

The equation used to calculate Gibbs free change is of a reaction is:

$\Delta G^o_{rxn}=\sum [n\times \Delta G^o_f_{(product)}]-\sum [n\times \Delta G^o_f_{(reactant)}]$

The equation for the Gibbs free energy change of the above reaction is:

$\Delta G^o_{rxn}=[(2\times \Delta G^o_f_{(Ag^+(aq.))})+(1\times \Delta G^o_f_{(S^{2-}(aq.))})]-[(1\times \Delta G^o_f_{(Ag_2S(s))})]$

We are given:

$\Delta G^o_f_{(Ag_2S(s))}=-39.5kJ/mol\\\Delta G^o_f_{(Ag^+(aq.))}=77.1kJ/mol\\\Delta G^o=285.794kJ$

Putting values in above equation, we get:

$285.794=[(2\times 77.1)+(1\times \Delta G^o_f_{(S^{2-}(aq.))})]-[(1\times (-39.5))]\\\\\Delta G^o_f_{(S^{2-}(aq.))=92.094J/mol$

Hence, the standard free energy change of formation of $S^{2-}(aq.)$ is 92.094 kJ/mol

8 0

3 years ago

2c2h6 + 7o2 = 4co2 + 6h2o what mass of co2 will be produced from the reaction of 37.5 g c2h6

ivanzaharov [21]

Answer:

use n=m/M (moles=mass/molar mass) to find out how many moles of C2H6 there are in 60g

Explanation:

8 0

2 years ago

How many meters are in one yard? 1m=1.09​

How many meters are in one yard? 1m=1.09