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The magnitude of the force is F=1.68×10 ^20 N
<u>Explanation:</u>
<u>Given data</u>
q1 =1.5 10 ^6 q2=3.2 10^6 r=1.5
<u>We have the formula</u>
By the coulomb's law
F= K. q1 ×q2 / r²
The K value is given by
8.99 10^9 Nm²/ c²
substitute the values we get,
F= ( 8.99× 10^9 Nm²/ c²) ×(<u>1.5 ×10 ^6</u>)×(<u>3.2 ×10 ^6</u>)/ (1.6 m² )
F=1.68×10 ^20 N
The magnitude of the force is F=1.68×10 ^20 N
The amount of work done on the weights would be approximately 15.0 Kg of work
Answer:
<h2>The answer is 30 s</h2>
Explanation:
The time taken can be found by using the formula
v is the velocity
a is the acceleration
From the question we have
We have the final answer as
<h3>30 s</h3>
Hope this helps you
