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Elina [12.6K]
3 years ago
5

During a test, a solution placed on a sheet

Physics
1 answer:
suter [353]3 years ago
3 0

Answer:

B. Acidic

Explanation:

Neutral an Basic solutions wouldn't create any reaction

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If 2 grams of element X combine with 4 grams of element Y to form compound XY, how many grams of element Y would combine with 33
RUDIKE [14]
66 g of element Y is needed since the ratio between element X and element Y is 1:2
5 0
3 years ago
A boat moves at 10.8 m/s relative to the water. If the boat is in a river where the current is 2.00 m/s, how long does it take t
Ray Of Light [21]

Answer:

Option E is the correct answer.

Explanation:

Velocity of boat = 10.8 m/s

Velocity of river = 2 m/s

Relative velocity upstream = 10.8 - 2 = 8.8 m/s

            Displacement = Velocity x Time

            1100 = 8.8 x t₁

        Time in upstream, t₁ = 125 s  

Relative velocity downstream = 10.8 + 2 = 12.8 m/s

            Displacement = Velocity x Time

            1100 = 12.8 x t₂

        Time in downstream, t₂ = 86 s  

Total time = t₁ + t₂ = 125 + 86 = 211 s

Option E is the correct answer.           

8 0
4 years ago
The secondary coil of a step-up transformer provides the voltage that operates an electrostatic air filter. The turns ratio of t
Sphinxa [80]

Answer:

The power consumed by the air filter is 9.936 watts      

Explanation:

It is given that, the secondary coil of a step-up transformer provides the voltage that operates an electrostatic air filter.

Turn ratio of the transformer, \dfrac{N_s}{N_p}=\dfrac{46}{1}

Voltage of primary coil, V_p=120\ V

Current in the secondary coil, I_s=1.8\times 10^{-3}\ A

The power consumed by the air filter is :

P_s=I_s\times V_s...........(1)

For a transformer, \dfrac{N_s}{N_p}=\dfrac{V_s}{V_p}

So, P_s=I_s\times (\dfrac{N_s}{N_p})\times V_p

P_s=1.8\times 10^{-3}\times (\dfrac{46}{1})\times 120

P_s=9.936\ Watts

So, the power consumed by the air filter is 9.936 watts. Hence, this is the required solution.                

3 0
4 years ago
Read 2 more answers
If the coefficient of static friction is 0.357, and the same ladder makes a 58.0° angle with respect to the horizontal, how far
zavuch27 [327]

Answer: d= 0.57* l

Explanation:

We need to check that before ladder slips the length of ladder the painter can climb.

So we need to satisfy the equilibrium conditions.

So for ∑Fx=0, ∑Fy=0 and ∑M=0

We have,

At the base of ladder, two components N₁ acting vertical and f₁ acting horizontal

At the top of ladder, N₂ acting horizontal

And Between somewhere we have the weight of painter acting downward equal to= mg

So, we have N₁=mg

and also mg*d*cosФ= N₂*l*sin∅

So,

d=\frac{N2}{mg}*l * tan∅

Also, we have f₁=N₂

As f₁= чN₁

So f₁= 0.357 * 69.1 * 9.8

f₁= 241.75

Putting in d equation, we have

d= \frac{241.75}{69.1*9.8} *l * tan 58

d= 0.57* l

So painter can be along the 57% of length before the ladder begins to slip

3 0
4 years ago
Read 2 more answers
Plz help me find the answers
san4es73 [151]

Answer: Plastids are the site of manufacture and storage of important chemical compounds used by the cells of autotrophic eukaryotes

Explanation:

6 0
3 years ago
Read 2 more answers
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